Question

我想更新MySQL数据库WHERE UserName='$username'中的上传图片网址，但没有任何反应。

我已仔细检查过我的代码，但没有任何错误但仍然无效。

提示

$user_name是会话。 $user_name = mysqli_real_escape_string($con, $_SESSION['UserName']);
$con是连接

Php代码

function uploadImageFile($user_name) { // Note: GD library is required for this function

if ($_SERVER['REQUEST_METHOD'] == 'POST') {
    $iJpgQuality = 100;

    if ($_FILES) {
        // if no errors and size less than 250kb
        if (! $_FILES['image_file']['error'] && $_FILES['image_file']['size'] < 250 * 1024) {
            if (is_uploaded_file($_FILES['image_file']['tmp_name'])) {
                if (!is_dir('avatar')) {
                    mkdir('avatar');
                }
                // new unique filename
                $sTempFileName = 'avatar/' . md5(time().rand());
                // move uploaded file into cache folder
                move_uploaded_file($_FILES['image_file']['tmp_name'], $sTempFileName);

                // change file permission to 644
                @chmod($sTempFileName, 0644);

                $sResultFileName = copyImageFile('avatar/'.$user_name.'', $sTempFileName, 200, 200, $iJpgQuality);
                if ($sResultFileName) {

                $con = mysqli_connect("localhost","root","","ara") or die("Error " . mysqli_error($link));

                $avatar1=copyImageFile('avatar1/'.$user_name.'', $sTempFileName, 500, 500);
                $avatar2=copyImageFile('avatar2/'.$user_name.'', $sTempFileName, 700, 700);

                mysqli_query($con,"UPDATE profiles SET (AvatarImage,AvatarImageBig,AvatarImageSmall) = ('".$sResultFileName."','".$avatar1."','".$avatar2."') WHERE UserName = '$user_name'");   


                    @unlink($sTempFileName);

                    return $sResultFileName;
                }
            }
        }
    }
}
return false;
}

function copyImageFile($dirName, $originImageName, $iWidth, $iHeight, $iJpgQuality = 90) {
if (file_exists($originImageName) && filesize($originImageName) > 0) {        
    $aSize = getimagesize($originImageName); // try to obtain image info
    if (!$aSize) {
        @unlink($originImageName);
        return;
    }

    // check for image type
    switch($aSize[2]) {
        case IMAGETYPE_JPEG:
            $sExt = '.jpg';
            $vImg = @imagecreatefromjpeg($originImageName);
            break;
        /*case IMAGETYPE_GIF:
            $sExt = '.gif';

            // create a new image from file 
            $vImg = @imagecreatefromgif($sTempFileName);
            break;*/
        case IMAGETYPE_PNG:
            $sExt = '.png';
            $vImg = @imagecreatefrompng($originImageName);
            break;
        default:
            @unlink($originImageName);
            return;
    }

    // create a new true color image
    $vDstImg = @imagecreatetruecolor( $iWidth, $iHeight );

    // copy and resize part of an image with resampling
    imagecopyresampled($vDstImg, $vImg, 0, 0, (int)$_POST['x1'], (int)$_POST['y1'], $iWidth, $iHeight, (int)$_POST['w'], (int)$_POST['h']);

    // define a result image filename        
    if (!is_dir($dirName)) {
        mkdir($dirName);
    }
    $newImageName = $dirName . DIRECTORY_SEPARATOR . md5(time().rand()) . $sExt;

    // output image to file
    imagejpeg($vDstImg, $newImageName, $iJpgQuality);
    //@unlink($sTempFileName);

    return $newImageName;
}

return false;
}

$user_name = $_SESSION['UserName'];

$sImage = uploadImageFile($user_name);
echo '<img src="'.$sImage.'" />';

Answer 1

您的数据库连接和查询脚本中存在错误：

$con = mysqli_connect("localhost","root","","ara") or die("Error " . mysqli_error($link));

这里有一个未声明的$ link变量。它应该是$ con。无论如何，如果您没有成功连接，则无法调用mysqli_error（$ con）。您应该更好地测试您的连接，如：

$con = mysqli_connect("localhost","root","","ara");
// Check connection
if (mysqli_connect_errno()){
    echo "Failed to connect to MySQL: " . mysqli_connect_error(); 
}

请参阅http://www.w3schools.com/php/func_mysqli_error.asp

您的更新查询应为：

"UPDATE profiles SET AvatarImage = '".$sResultFileName."', AvatarImageBig = '".$avatar1."',AvatarImageSmall = '".$avatar2."' WHERE UserName = '$user_name'"

而不是

,"UPDATE profiles SET (AvatarImage,AvatarImageBig,AvatarImageSmall) = ('".$sResultFileName."','".$avatar1."','".$avatar2."') WHERE UserName = '$user_name'"

当然，您必须检查mysqli中已经注释的错误。

在MySQL数据库中更新上传的图像URL

1 个答案: