Question

如何使用大量正则表达式删除细节？

例如

删除前

：

Live => [US] United States | example1@yahoo.com | Checked on 5:59 pm - May 17, 2015 
Live => [US] United States | example2@yahoo.com | Checked on 5:59 pm - May 17, 2015 
Live => [US] United States | example3@yahoo.com | Checked on 5:59 pm - May 17, 2015 
Live => [US] United States | example4@yahoo.com | Checked on 5:59 pm - May 17, 2015 
Live => [US] United States | example5@yahoo.com | Checked on 5:59 pm - May 17, 2015

删除后：

example1@yahoo.com
example2@yahoo.com
example3@yahoo.com
example4@yahoo.com
example5@yahoo.com

请在regex101上使用demo演示:)

之前谢谢

Answer 1

您可以使用以下内容进行匹配：

.*?\s*\|\s*(.*?)\s*\|.*

并替换为$1

请参阅DEMO

Answer 2

使用下面的正则表达式，然后用空字符串替换匹配。

^[^|]*\|\s*|\s*\|.*

DEMO

在php中，您需要使用preg_replace函数。

$re = "/^[^|]*\\|\\s*|\\s*\\|.*/m";
$str = "Live => [US] United States | example1@yahoo.com | Checked on 5:59 pm - May 17, 2015 \nLive => [US] United States | example2@yahoo.com | Checked on 5:59 pm - May 17, 2015 \nLive => [US] United States | example3@yahoo.com | Checked on 5:59 pm - May 17, 2015 \nLive => [US] United States | example4@yahoo.com | Checked on 5:59 pm - May 17, 2015 \nLive => [US] United States | example5@yahoo.com | Checked on 5:59 pm - May 17, 2015 ";
$subst = "";
$result = preg_replace($re, $subst, $str);
echo $result;

如何清理正则表达式的细节质量

2 个答案: