我必须编写此脚本来分隔在命令行中输入的参数。 到目前为止,这是脚本:
# template.sh
function usage
{
echo "usage: $0 arguments ..."
if [ $# -eq 1 ]
then echo "ERROR: $1"
fi
}
# Script starts after this line.
case $1 in
*?)echo "My Name"
date
echo
echo $*
echo "*****"
;;
*)usage
;;
esac
我需要获得的是当我使用它需要的脚本时:
$ ./template.sh peter frederick chang
My Name
Sun May 17 11:28:46 PDT 2015
peter
*****
frederick
*****
chang
*****
但相反,我得到了:
$ ./template.sh peter frederick chang
My Name
Sun May 17 11:28:46 PDT 2015
peter frederick chang
*****
答案 0 :(得分:3)
使用printf
代替echo
这样的"$@"
来打印不同行的参数:
# Script starts after this line.
case $1 in
*?)echo "My Name"
date
echo
printf "%s\n*****\n" "$@"
;;
*)usage
;;
esac
这将打印:
My Name
Sun May 17 06:50:26 EDT 2015
peter
*****
frederick
*****
chang
*****