Question

我试图在实际表单中验证表单，但它根本没有得到验证。如果我输入＆＃34; someemail＆amp; *！（[] @ gmail.com＆＃34;，它并没有真正给出废话并继续前进。表格：

class RecoverPasswordForm extends Form {
    public function __construct($options = null) {
        parent::__construct("RecoverPassword");

        $username = new Element("username");
        $username->setLabel("Email");
        $username->setAttributes(
            array('filters' => array(
                array('name' => 'StringTrim'),
                array('name' => 'StripTags')),
                'validators' => array(
                    array(
                        'name' => 'Regex',
                        'options' => array(
                            'pattern' => '/^[a-zA-Z0-9.!#$%&\'*+\/=?^_`{|}~-]+@[a-zA-Z0-9-]+(?:\.[a-zA-Z0-9-]+)*$/',
                            'messages' => array(
                                Regex::NOT_MATCH => 'The email your provided has invalid characters.',
                            ),
                        ),
                        'break_chain_on_failure' => true
                    ),
                    array(
                        'name' => 'EmailAddress',
                        'options' => array(
                            'messages' => array(
                                EmailAddress::INVALID_FORMAT => "Email address is invalid",
                                EmailAddress::INVALID => "",
                                EmailAddress::INVALID_LOCAL_PART => "",
                                EmailAddress::INVALID_HOSTNAME => "",
                                EmailAddress::INVALID_SEGMENT => "",
                                EmailAddress::DOT_ATOM => "",
                                EmailAddress::INVALID_MX_RECORD => "",
                            ),
                        ),
                    ),
                ),
                'label' => 'Email'));
        $this->add(array(
            $username,

        ));
    }
}

我如何获得（或试图获得）控制器中的过滤器和验证器：

      public function recoverPasswordAction() {
        $this->cache = new Container("cache");
        $request = $this->getRequest();
        $form = new RecoverPasswordForm();
//      $form->get("submit")->setValue("Send mail");
        $this->view->form = $form;
        if ($request->isPost()) {
            $user = new User();
            $form->getInputFilter()->getValues();
            $form->setInputFilter($form->getInputFilter());
            $data = $request->getPost();
            $form->setData($data);
            $username = $data['username'];
            $userData = $this->getServiceLocator()->get("UserTable")->fetchList("`username` LIKE '$username'");
            if (!count($userData) > 0) {
                $this->cache->error = "A user with this email does not exist, plese try again.";
            }
                if ($form->isValid()) {
                    foreach ($userData as $user) {
                        $user->sendMail(6);
                        $this->cache->success = "A message has been send to this email, containing your password.";
                    }
                }
        }
        return $this->view;
    }

Answer 1

试试这个......

$request = $this->getRequest();

$form = new Form();

if($request->isPost()) {
    if($form->isValid($reguest->getPost())) {
        $values = $form->getValues(); //filtered valid array of values

        $username = $form->getValue('username');


    }
}
$this->view->form = $form;

Answer 2

我认为这是因为验证器的实施错误。

您可以尝试在表单上实施InputProviderInterface吗？基本示例在docs中给出。它在元素上设置，但您也可以在表单上执行此操作。此接口定义getInputSpecification，您必须返回一个包含过滤器和验证器规范的数组。

Zend - 形式没有得到验证

2 个答案: