Question

我在这个领域是全新的，我的问题很简单，但我找不到任何解决方案。我试图在Activity中创建ListView。我试过这个教程：（http://www.androidhive.info/2012/02/android-custom-listview-with-image-and-text/）。我想用我的数据XML文件替换music.xml。但我必须交换＆＃34; http://api.androidhive.info/music/music.xml＆＃34; [第5行]将我的XML文件放入我的硬盘（在Android项目中）。

package com.example.androidhive;


import android...;

public class CustomizedListView extends Activity {
// All static variables
static final String URL = "http://api.androidhive.info/music/music.xml";
// XML node keys
static final String KEY_SONG = "song"; // parent node
static final String KEY_ID = "id";
static final String KEY_TITLE = "title";
static final String KEY_ARTIST = "artist";
static final String KEY_DURATION = "duration";
static final String KEY_THUMB_URL = "thumb_url";

ListView list;
LazyAdapter adapter;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);


    ArrayList<HashMap<String, String>> songsList = new ArrayList<HashMap<String, String>>();

    XMLParser parser = new XMLParser();
    String xml = parser.getXmlFromUrl(URL); // getting XML from URL
    Document doc = parser.getDomElement(xml); // getting DOM element

    NodeList nl = doc.getElementsByTagName(KEY_SONG);
    // looping through all song nodes <song>
    for (int i = 0; i < nl.getLength(); i++) {
        // creating new HashMap
        HashMap<String, String> map = new HashMap<String, String>();
        Element e = (Element) nl.item(i);
        // adding each child node to HashMap key => value
        map.put(KEY_ID, parser.getValue(e, KEY_ID));
        map.put(KEY_TITLE, parser.getValue(e, KEY_TITLE));
        map.put(KEY_ARTIST, parser.getValue(e, KEY_ARTIST));
        map.put(KEY_DURATION, parser.getValue(e, KEY_DURATION));
        map.put(KEY_THUMB_URL, parser.getValue(e, KEY_THUMB_URL));

        // adding HashList to ArrayList
        songsList.add(map);
    }


    list=(ListView)findViewById(R.id.list);

    // Getting adapter by passing xml data ArrayList
    adapter=new LazyAdapter(this, songsList);        
    list.setAdapter(adapter);


    // Click event for single list row
    list.setOnItemClickListener(new OnItemClickListener() {

        @Override
        public void onItemClick(AdapterView<?> parent, View view,
                int position, long id) {


        }
    });     
}   
}

例如，我的music.xml位于assets文件夹中。为什么我不能把它放在res / values中？

Answer 1

在XMLParser课程中添加新方法，我们说getXMLFromAssets(String fileName, Context context)。像这样实现它。

public String getXMLFromAssets(String fileName, Context context) {

    StringBuilder returnString = new StringBuilder();
    InputStream inputStream = null;
    InputStreamReader inputStreamReader = null;
    BufferedReader input = null;

    try {
        inputStream = context.getResources().getAssets()
                .open(fileName, Context.MODE_WORLD_READABLE); // Context.MODE_WORLD_READALE is maybe not necessary
        inputStreamReader = new InputStreamReader(inputStream);
        input = new BufferedReader(inputStreamReader);
        String line = "";

        while ((line = input.readLine()) != null) {
            returnString.append(line);
        }

    } catch (Exception e) {
        e.getMessage();
    } finally {
        try {
            if (inputStreamReader != null)
                inputStreamReader.close();
            if (inputStream != null)
                inputStream.close();
            if (input != null)
                input.close();
        } catch (Exception e) {
            e.getMessage();
        }
    }
    return returnString.toString();
}

这样您就可以以String格式从assets文件夹中获取XML，并且可以照常继续。

我使用了此post中的此方法。

如何将XML数据文件从我的硬盘驱动器（而不是Web）链接到我的项目？

1 个答案: