将字符串从处理发送到Arduino不起作用

时间:2015-05-16 19:54:56

标签: c string arduino processing

我在处理过程中收集了一些字符串信息,我正在尝试将其发送给Arduino。我正在处理发送信息,但是,我在arduino中的输出很奇怪。我得到像“77789 ......”这样的数字。我不确定我做错了什么。我需要做的就是,基本上从处理中获取一个字符串并将其发送到arduino以在LCD屏幕上显示它。

对此有任何帮助将不胜感激。

这是我的处理代码:

import processing.serial.*;

Serial myPort;

XML MSFTxml; // loading Query

XML MSFT; // results of the query
XML row; // first row in the query

XML symbol; // Name of the stock
String symbolTxt;


String val;

void setup() {
  size(200,200);
  myPort = new Serial(this,"COM3", 9600);

}

void draw() {

updateXMLCall();

delay(10000);
}
void updateXMLCall () {

   MSFTxml = loadXML("https://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20csv%20where%20url%3D%27http%3A%2F%2Fdownload.finance.yahoo.com%2Fd%2Fquotes.csv%3Fs%3DMSFT%26f%3Dsl1d1t1c1ohgv%26e%3D.csv%27%20and%20columns%3D%27symbol%2Cprice%2Cdate%2Ctime%2Cchange%2Ccol1%2Chigh%2Clow%2Ccol2%27&format=xml&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys");  
   MSFT = MSFTxml.getChild("results"); //Getting the first tag "results" in the query MSFT
   row= MSFT.getChild("row"); //first child tag "row"
   symbol = row.getChild("symbol"); //name of the stock   
   symbolTxt = symbol.getContent().toString(); //converting the name of the stock into a string
   myPort.write(symbolTxt);
   println(symbolTxt);
}

这是我的arduino代码:

#include <Wire.h>
#include "rgb_lcd.h"
rgb_lcd lcd;

const int colorR = 50;
const int colorG = 0;
const int colorB = 0;

void setup()
{
  Serial.begin(9600);
  // set up the LCD's number of columns and rows:
  lcd.begin(16, 2);
  lcd.setRGB(colorR, colorG, colorB);
  // Print a message to the LCD.
  lcd.setCursor(0, 1);
}

void loop()
{  
  String content = "";
  if (Serial.available()) {
    while (Serial.available()) {
      content += Serial.read();
      lcd.print(content);
      Serial.print(content);
      lcd.setCursor(0, 1);
    }
  }
  delay(100);
}

1 个答案:

答案 0 :(得分:1)

问题是在+=中使用+=并不会连接字符串。 您需要在此处连接char来自Serial.read(),例如: Convert serial.read() into a useable string using Arduino?