我试图在mysql数据库的每个返回结果行的末尾添加一个链接,该链接将我发送到另一个php页面,这将允许我编辑行中的数据。问题是我无法找到应该添加链接代码的代码的哪一部分,这样无论返回多少结果,每行末尾都会出现一个编辑链接。
这是我目前用来检索结果的php代码。
<?php
echo "<table style='border: solid 1px black;'>";
echo "<tr><th>Booking Ref</th><th>First Name</th><th>Last Name</th><th>Contact Number</th><th>Booked Date</th><th>Adults</th><th>Juniors</th><th>Paintballs</th><th>Edit</th></tr>";
class TableRows extends RecursiveIteratorIterator {
function __construct($it) {
parent::__construct($it, self::LEAVES_ONLY);
}
function current() {
return "<td style='width:150px;border:1px solid black;'>" . parent::current(). "</td>";
}
function beginChildren() {
echo "<tr>";
}
function endChildren() {
echo "</tr>" . "\n";
}
}
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "login";
$u_name = $_SESSION['user_name'];
try {
$conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$stmt = $conn->prepare("SELECT booking_id, fname, lname, phone_number, date, adults, juniors, paintballs FROM bookings INNER JOIN users ON users.user_name = bookings.user_name WHERE users.user_name = '" . $u_name . "'");
$stmt->execute();
// set the resulting array to associative
$result = $stmt->setFetchMode(PDO::FETCH_ASSOC);
foreach(new TableRows(new RecursiveArrayIterator($stmt->fetchAll())) as $k=>$v) {
echo $v;
}
}
catch(PDOException $e) {
echo "Error: " . $e->getMessage();
}
$conn = null;
echo "</table>";
?>
&#13;
非常感谢任何帮助,提前谢谢!
答案 0 :(得分:0)
您可以将其放在endChildren()
方法中。
但我完全不确定如何访问行数据(你显然需要行ID来编辑它)。