Question

以下问题让我感到困惑。我想从关系中删除测量值，并且引用的对象应该更新测量值。那么我的问题是什么，如果我删除一个测量，哪个工作正常，但如果我从固化对象获得所有测量，我看到删除对象在里面。刷新关系的最佳方法是什么？

Measurement.java

@Entity
@Table(name = "measurements")
public class Measurement extends Model {

    @Id
    public Long id;

    @Formats.DateTime(pattern = "dd.MM.yyyy")
    public Date created = new Date();

    @Constraints.Required
    public double weight;

    @Constraints.Required
    public double belly;

    @Constraints.Required
    public double thigh;

    @Constraints.Required
    public double gluteal;

    @ManyToOne
    @JsonBackReference
    public Cure cure;
}

Cure.java

@Entity
@Table(name = "cures")
public class Cure extends Model  implements Comparable<Cure> {

    @Id
    public Long id;

    @Formats.DateTime(pattern = "dd.MM.yyyy")
    public Date created = new Date();

    public int startHour = 10;

    @ManyToOne
    @JsonIgnore
    public Challenge challenge;

    @JsonManagedReference
    @OneToMany
    public List<Measurement> measurements;
}

应该处理删除的行动

public static Result delete(Long id){
    Measurement measurement = Measurement.find.byId(id);

    if(measurement == null && !measurement.belongsToUser(user)){
        return noContent();
    }

    measurement.delete();
    return ok();
}

Answer 1

嗯，我没有在你的模特课上看到发现者。实施以下

public static Finder<Long, Measurement> find = new Finder<Long, Measurement>(Long.class, Measurement.class);

然后试试。此外，ebean有很多问题你可以使用原始查询删除，如下所示

SqlUpdate deletObject = Ebean
                        .createSqlUpdate("delete from table_name where id = "
                                + id); 
deletObject.execute();

Ebean删除对象不刷新实际情况

1 个答案: