Question

请有人帮助我。在下面的代码中，查询将执行3次，意味着查询执行将取决于数组中的元素数量。请指导我如何通过一次插入所有数据来运行此查询

 $products = array("shirt" , "paint" , "socks");
    $price = array("200" , "600" , "50");
    $quantity = array("3" , "2" , "2");

        $num = 0; while($num <= count($products))
        {
            $mysqli->query("insert into new_order set 
                            product = '".$products[$num]."' ,
                            price = '".$price[$num]."' , 
                            quantity = '".$quantity[$num]."'
                          ");

                          $num++;
        }

Answer 1

迭代$products中的每个项目以构建$sql字符串：

$sql = "insert into new_order(product, price, quantity) values ";
for($i=0;$i<count($products);$i++){
    $sql .= "({$products[$i]}, {$price[$i]}, {$quantity[$i]}),";
}
$sql = substr($sql,0,-1); //cut off the trailing comma
$mysqli->query($sql);

// insert into new_order(product, price, quantity) values (shirt, 200, 3),(paint, 600, 2),(socks, 50, 2)

Answer 2

它不会抛出任何错误，直到您在数组中获得相同数量的值

$counts = count($products);
$query = "insert into new_order (product,price,quantity) values ";
foreach($products as $key => $value){
    $query .= "('$value','$price[$key]','$quantity[$key]')";
    $query .= (++$key == $counts) ? '' : ',';
}
$mysqli->query($query);

查询看起来像：

//insert into new_order (product,price,quantity) values('shirt','200','3'),('paint','600','2'),('socks','50','2')

如何在单个查询中插入多个值

2 个答案: