Question

我一直在寻找一个解决方案，让我的程序检查我的窗口是否被激活。

您可以检查底部的系统属性，并说明剩余xx天，点击此处激活。这样我知道它没有激活。

问题是我使用了以下代码：

Imports System.Collections.Generic
Imports System.Text
Imports System.Runtime.InteropServices
Imports SLID = System.Guid
Module Genuine_Check

    Public Enum SL_GENUINE_STATE
        SL_GEN_STATE_IS_GENUINE = 0
        SL_GEN_STATE_INVALID_LICENSE = 1
        SL_GEN_STATE_TAMPERED = 2
        SL_GEN_STATE_LAST = 3
    End Enum

    <DllImportAttribute("Slwga.dll", EntryPoint:="SLIsGenuineLocal", CharSet:=CharSet.None, ExactSpelling:=False, SetLastError:=False, PreserveSig:=True, CallingConvention:=CallingConvention.Winapi, _
     BestFitMapping:=False, ThrowOnUnmappableChar:=False)> _
    <PreserveSigAttribute()> _
    Friend Function SLIsGenuineLocal(ByRef slid As SLID, <[In](), Out()> ByRef genuineState As SL_GENUINE_STATE, ByVal val3 As IntPtr) As UInteger
    End Function


    Public Function IsGenuineWindows() As Boolean
        Dim _IsGenuineWindows As Boolean = False
        Dim ApplicationID As New Guid("55c92734-d682-4d71-983e-d6ec3f16059f")
        'Application ID GUID http://technet.microsoft.com/en-us/library/dd772270.aspx
        Dim windowsSlid As SLID = CType(ApplicationID, Guid)
        Try
            Dim genuineState As SL_GENUINE_STATE = SL_GENUINE_STATE.SL_GEN_STATE_LAST
            Dim ResultInt As UInteger = SLIsGenuineLocal(windowsSlid, genuineState, IntPtr.Zero)
            If ResultInt = 0 Then
                _IsGenuineWindows = (genuineState = SL_GENUINE_STATE.SL_GEN_STATE_IS_GENUINE)
            Else
                MsgBox("Error getting information {0}", ResultInt.ToString())

            End If
        Catch ex As Exception
            MsgBox(ex.Message)
        End Try
        Return _IsGenuineWindows
    End Function

    Public Function CheckGenuine()

        If Environment.OSVersion.Version.Major >= 6 Then
            'Version 6 can be Windows Vista, Windows Server 2008, or Windows 7
            If IsGenuineWindows() Then
                MsgBox("Original Windows")
                Form1.Button8.BackColor = Color.LawnGreen
            Else
                MsgBox("Not Original Windows")
                Form1.Button8.BackColor = Color.Red
            End If
        Else
            MsgBox("OS Not supported")
        End If
    End Function
    End Module

然后我运行以下内容：

 Private Sub Button8_Click(sender As Object, e As EventArgs) Handles Button8.Click
        Try
            CheckGenuine()
        Catch ex As Exception
            MsgBox(ex.Message, MsgBoxStyle.Critical + MsgBoxStyle.OkOnly)
        End Try

但是这显示了一个消息：带有密钥的系统上的'原始Windows'，并且在没有安装密钥的情况下激活了干净安装。

所以我的问题是不要看我的窗户是否是原装的，但是如果它仍然需要激活。

有没有办法完成这项工作？或者有关如何使这项工作的任何提示？

Answer 1

我设法解决了问题，使用完全不同的解决方案，如上所述，我正在查看错误的解决方案和代码。

如果有人感兴趣，以下是解决方案。

 Private Sub Button8_Click(sender As Object, e As EventArgs) Handles Button8.Click
        Try

            Dim searcher As New ManagementObjectSearcher( _
                  "root\CIMV2", _
                  "SELECT * FROM SoftwareLicensingProduct WHERE LicenseStatus = 1")
            Dim myCollection As ManagementObjectCollection
            Dim myObject As ManagementObject
            myCollection = searcher.Get()
            If myCollection.Count = 0 Then
                MsgBox("Windows is not activated")
                Button8.BackColor = Color.Red
                searcher.Dispose()
            Else

                For Each myObject In myCollection

                    MsgBox("Windows is activated")
                    Button8.BackColor = Color.LawnGreen
                    searcher.Dispose()

                Next
            End If
            searcher.Dispose()
        Catch ex As Exception
            MsgBox(ex.Message, MsgBoxStyle.Critical + MsgBoxStyle.OkOnly)
        End Try

VB.NET检查WIndows是否被激活

1 个答案: