Question

我有一个SharePoint生成的页面。从那里我试图从下面的例子中提取第二个<td>值。如何使用jQuery遍历代码并获取该值？

   <span id="part1">
       <table cellpadding="0" cellspacing="0" width="100%"><tbody><tr><td align="right" width="100%" nowrap="nowrap">
        <tbody>
           <tr>
    <td nowrap="true" valign="top" width="113px" class="ms-formlabel"><h3 class="ms-standardheader"><a name="SPBookmark_Title"></a>Title</h3></td>
    <td valign="top" class="ms-formbody" width="350px" id="SPFieldText">
    <!-- FieldName="Title"
         FieldInternalName="Title"
         FieldType="SPFieldText"
      -->
        Test Project
    </td>
</tr>
        </tbody>
       </table>
    </span>

我试过了：

    $('#part1 table tbody tr:nth-child(1)').each(function() {
    titleTxt = $(this).find(".ms-formbody").html();  
        alert(titleTxt);
});

但我得到了垃圾值。

更新

我像这样使用$('#part1 > table:first tr:first td:nth-child(2)').html();并获得结果

<!-- FieldName="Title"
         FieldInternalName="Title"
         FieldType="SPFieldText"
      -->
        Test Project

如何评论igrone

Answer 1

尝试

import akka.actor.ActorRef;
import akka.actor.ActorSelection;
import akka.actor.ActorSystem;
import akka.actor.Props;
import akka.actor.UntypedActor;

public class Messenger extends UntypedActor {

private static ActorRef hero;

public Messenger() {
    ActorSelection master = context().actorSelection("akka.tcp://testHero@127.0.0.1:2552/user/master");
    System.out.println(master);
    hero = master.anchor();

}

@Override
public void onReceive(Object arg0) throws Exception {
    System.out.println("msg = " + arg0);
}


public static void main(String[] args) {
    ActorSystem system = ActorSystem.create("test");
    ActorRef actor = system.actorOf(Props.create(Messenger.class), "msgnr");
    System.out.println(actor.getClass() + " >> " + actor);
    System.out.println(hero);
    actor.tell("Hi", hero);
}

}

或者

$('#part1 table tr:first td:nth-child(2)').html()

从表td文件SharePoint标题？

更新

1 个答案: