Question

我继承了一个转换为数据库的excel文件，我试图找出去过多个地点的人。

| Customer    | email          |   ZIP | shop |
| John Smith  | js@mail.com    | 75016 |    1 |
| Mary King   | mary@ymail.com | 97430 |    2 |
| John Smith  | js@mail.com    | 75016 |    3 |
| Ivan Turtle | ivan@mail.com  | 56266 |    5 |
| Mary King   | mary@ymail.com | 97430 |    5 |
| John Smith  | js@mail.com    | 75016 |    5 |

例如：John Smith去过1,3,5 玛丽金到2,3，

我尝试使用电子邮件作为密钥，但无法弄清楚如何解决这个问题

Answer 1

假设每行指定一个单独的位置，

select customer, count(*)  as countOfLocation
from TABLE
group by customer
having count(*) > 1
order by countOfLocation desc

是最简单的答案

Answer 2

我相信这样的事情会对你有用。

查找前往多家商店的所有客户，然后加入以获取每位客户的详细信息。

这将为每个人提供多行，每个商店都有一行。如果你关心的只是客户的名字，你可以简单地使用第二个SELECT

如果您想要每个客户一行和商店的CSV，您将需要进行一些加入。

SELECT a.*
FROM Customers a
INNER JOIN 

-- Find all customers who have been to more than one shop.
(SELECT email
FROM Customers
GROUP BY email
HAVING COUNT(shop) > 1) b

ON a.email = b.email

Answer 3

尝试使用这个，如果是Sql server：

select customer, count(distinct(shop))
from table
group by customer, shop
having count(distinct(shop)) > 1

或者，您只想知道他们访问了多少个地方：

 select customer, count(distinct(shop))
    from table
    group by customer, shop

Answer 4

如果您想显示用户名并在一行中用逗号分隔，请使用此

SELECT  Customer
       ,STUFF((SELECT ', ' + CAST(shop AS VARCHAR(10)) [text()]
         FROM 'ur table'
         WHERE customer = t.customer
         FOR XML PATH(''), TYPE)
        .value('.','NVARCHAR(MAX)'),1,2,' ') List_Output
FROM 'ur table' t
GROUP BY customer

同一桌子上的几个条件

4 个答案: