我无法在php中使用此代码..我正在使用Dreamweaver
{
<SCRIPT language = "JavaScript">
var counter = 0;
// call Update function in 2 seconds after first load
ID = window . setTimeout("Update();", 2000);
function Update() {
counter++;
window.status = "The counter is now at " + counter;
document.form1.input1.value = "The counter is now at " + counter;
// set another timeout for the next count
ID = window . setTimeout("Update();", 2000);
}
</SCRIPT>
}
答案 0 :(得分:1)
您没有输出脚本:页面需要具有用于执行JavaScript的HTML内容(通过浏览器)。 Echo你的剧本并从那里开始。
<?php
{
echo'<SCRIPT language = "JavaScript">
var counter = 0;
// call Update function in 2 seconds after first load
ID = window . setTimeout("Update();", 2000);
function Update() {
counter++;
window.status = "The counter is now at " + counter;
document.form1.input1.value = "The counter is now at " + counter;
// set another timeout for the next count
ID = window . setTimeout("Update();", 2000);
}
</SCRIPT>';
} ?>