Question

我有下表结构。（我是SQL Lite的新手）

create table Relations 
(
Code int,
ParentCode int ,
fname text
)
GO
insert into Relations values(1,null,'A');
insert into Relations values(2,null,'B');
insert into Relations values(3,2,'C');
insert into Relations values(4,3,'D');

我想得到Code = 4的初始父代：即值2无效B

我无法弄清楚如何在sqllite中编写递归查询。在此先感谢..

Answer 1

版本问题.. 此查询无效＆amp;得到了语法错误。我从3.7.17升级到3.8.7.4版本＆amp;它工作..

WITH RECURSIVE
  works(Code,Parent) AS (
   Select Code,ParentCode from Relations a where a.Code=4
    UNION
    SELECT Relations.Code, Relations.ParentCode FROM Relations , works
     WHERE Relations.Code=works.Parent
  )
SELECT * FROM works where Parent is null

SQL Lite中的递归查询CTE

1 个答案: