Controller.ValidateModel方法。它是如何工作的?

时间:2015-05-15 12:41:35

标签: validation asp.net-mvc-5 ivalidatableobject

我有以下模型类:

public abstract class CompanyFormViewModelBase
{
    public CompanyFormViewModelBase()
    {
        Role = new CompanyRoleListViewModel();
        ContactPerson = new PersonListViewModel();
        Sector = new SectorListViewModel();
    }
    [Required]
    [Display(Name = "Company Name")]
    public string CompanyName { get; set; }
    public CompanyRoleListViewModel Role { get; set; }
    [Display(Name = "Contact Name")]
    public PersonListViewModel ContactPerson { get; set; }
    public SectorListViewModel Sector { get; set; }
}
public class AddCompanyViewModel : CompanyFormViewModelBase, IValidatableObject
{
    public IEnumerable<ValidationResult> Validate(ValidationContext validationContext)
    {
        PlugandabandonEntities db = new PlugandabandonEntities();
        CompanyName = CompanyName.Trim();

        var results = new List<ValidationResult>();

        if (db.Company.Where(p => p.CompanyName.ToLower() == CompanyName.ToLower()).Count() > 0)
            results.Add(new ValidationResult("Company already exists.", new string[] { "CompanyName" }));
        return results;
    }
}

使用“经典”可以正常使用:

    [HttpPost]
    [ValidateAntiForgeryToken]
    public ActionResult Create(Plugandabandon.ViewModels.AddCompanyViewModel model)
    {
        if (ModelState.IsValid)
        {
            CreateCompany(model);
            return RedirectToAction("Index");
        }
        else
        {
            return View(model);
        }
    }

但是我想将这个模型类用于另一个,ajax形式。 我有以下方法:

   public JsonResult ReturnJsonAddingCompany(string companyName, int roleID, int sectorID, int personID)
    {
        Plugandabandon.ViewModels.AddCompanyViewModel model = new ViewModels.AddCompanyViewModel()
        {
            CompanyName = companyName,
            ContactPerson = new ViewModels.PersonListViewModel()
            {
                SelectedItem = personID
            },
            Role = new ViewModels.CompanyRoleListViewModel()
            {
                SelectedItem = roleID
            },
            Sector = new ViewModels.SectorListViewModel()
            {
                SelectedItem = sectorID
            }
        };

        ValidateModel(model);

        if (ModelState.IsValid)
        {
            CreateCompany(model);
        }
        else
        {
            throw new Exception("Company with such name already exists");
        }

        var list = Utils.CompanyList();
        return Json(list, JsonRequestBehavior.AllowGet);
    }

看看

    ValidateModel(model);

线。如果模型是正确的 - 它工作正常。如果不正确 - 它会抛出异常并中断方法的继续执行(并返回异常以查看)。另外,如果我在

上设置断点
public IEnumerable<ValidationResult> Validate(ValidationContext validationContext)

方法,它永远不会在无效的模型案例中调用! (调用有效模型Validate方法)。我想拥有像“经典”方法这样的行为,只需验证模型然后验证ModelState.IsValid。 ValidateModel(模型)的行为对我来说很奇怪,它是一个“黑盒子”......

1 个答案:

答案 0 :(得分:3)

如果模型无效,

ValidateModel()会抛出异常。相反,请使用TryValidateModel()

来自documentation

  

TryValidateModel()与ValidateModel()方法类似,只是如果模型验证失败,TryValidateModel()方法不会抛出InvalidOperationException异常。