我正在使用winforms / c#尝试拖拽面板中的tablelayoutpanel,tablelayout的拖动效果很好,但问题是tablelayoutpanel droped没有出现! 任何解决方案吗??
private void Registration_Load(object sender, EventArgs e)
{
panel2.AllowDrop = true;
tableLayoutPanel1.AllowDrop = true;
panel2.DragEnter += panel2_DragEnter;
panel2.DragDrop += panel2_DragDrop;
tableLayoutPanel1.MouseDown += tableLayoutPanel1_MouseDown;
}
private void panel2_DragEnter(object sender, DragEventArgs e)
{
e.Effect = DragDropEffects.Move;
}
private void panel2_DragDrop(object sender, DragEventArgs e)
{
((TableLayoutPanel)e.Data.GetData(typeof(TableLayoutPanel))).Parent (Panel)sender;
}
private void tableLayoutPanel1_MouseDown(object sender, MouseEventArgs e)
{
tableLayoutPanel1.DoDragDrop(tableLayoutPanel1, DragDropEffects.Move);
}
答案 0 :(得分:0)
代码不足,您至少需要设置丢弃的TLP的Location属性,以确保它位于面板边界内和/或位于鼠标光标处。并且Z顺序很重要,设置Parent属性将其置于底部,以便它可以轻松地与面板中的其他控件重叠,您需要BringToFront()。
试试这个:
private void panel2_DragEnter(object sender, DragEventArgs e) {
if (e.Data.GetDataPresent(typeof(TableLayoutPanel))) e.Effect = DragDropEffects.Move;
}
private void panel2_DragDrop(object sender, DragEventArgs e) {
var tlp = (TableLayoutPanel)e.Data.GetData(typeof(TableLayoutPanel));
tlp.Location = panel2.PointToClient(new Point(e.X, e.Y));
tlp.Parent = panel2;
tlp.BringToFront();
}