Question

    > df<-read.csv("weatherdatatrail.csv")
    > header=T
    > df$Date
    [1] 01-01-1989 01-02-1989 01-03-1989 01-04-1989 01-05-1989 01-06-1989
    [7] 01-07-1989 01-08-1989 01-09-1989 01-10-1989 01-11-1989 01-12-1989
    [13] 1/13/1989  1/14/1989  1/15/1989  1/16/1989  1/17/1989  1/18/1989 
    [19] 1/19/1989  1/20/1989  1/21/1989  1/22/1989  1/23/1989  1/24/1989 
    [25] 1/25/1989  1/26/1989  1/27/1989  1/28/1989  1/29/1989  1/30/1989 
    [31] 1/31/1989 
    31 Levels: 01-01-1989 01-02-1989 01-03-1989 01-04-1989 ... 1/31/1989

在为以下代码执行R时，它适用于通用格式，但对于日期格式，它显示为NA ..

   > df$Date<-as.Date(as.character(df$Date),format="%m/%d/%Y")
   > str(df)
   'data.frame':   31 obs. of  10 variables:
    $ Date             : Date, format: NA NA ...
    $ Longitude        : num  77.2 77.2 77.2 77.2 77.2 ...
    $ Latitude         : num  11.4 11.4 11.4 11.4 11.4 ...
    $ Elevation        : int  282 282 282 282 282 282 282 282 282 282 ...
    $ Max.Temperature  : num  28.2 28.5 29.6 29.3 27.9 ...
    $ Min.Temperature  : num  10.9 15.4 14.2 16.5 16.3 ...
    $ Precipitation    : num  0 0.0378 0.0893 0.2077 0.1785 ...
    $ Wind             : num  2.17 2.1 2.03 2.05 2.09 ...
    $ Relative.Humidity: num  0.559 0.705 0.718 0.779 0.781 ...
    $ Solar            : num  21 20.5 19.3 19.2 14.8 ...

    > df$Date
   [1] NA           NA           NA           NA           NA          
   [6] NA           NA           NA           NA           NA          
   [11] NA           NA           "1989-01-13" "1989-01-14" "1989-01-15"
   [16] "1989-01-16" "1989-01-17" "1989-01-18" "1989-01-19" "1989-01-20"
   [21] "1989-01-21" "1989-01-22" "1989-01-23" "1989-01-24" "1989-01-25"
   [26] "1989-01-26" "1989-01-27" "1989-01-28" "1989-01-29" "1989-01-30"
   [31] "1989-01-31"

我无法取得完美的结果..请帮帮我

Answer 1

您可以使用library(lubridate)（由@MrFlick评论）

library(lubridate)
as.Date(mdy(v1))
#[1] "1989-01-01" "1989-01-02" "1989-01-15"

数据

v1 <- c("01-01-1989", "01-02-1989", "1/15/1989")

Answer 2

您可以将日期列更改为相同的格式，然后将其转换为日期类型

dates <- c("01-01-1989" ,  "01-02-1989"  , "01-03-1989" , "01-04-1989" ,  "01-05-1989" , "01-06-1989" , 
           "01-07-1989" , "01-08-1989" , "01-09-1989" , "01-10-1989" ,  "01-11-1989" ,"01-12-1989" , 
           "1/13/1989" ,  "1/14/1989" , "1/15/1989"  ,"1/16/1989" ,  "1/17/1989",  "1/18/1989" , 
           "1/1/1989")

df <- data.frame(Date = dates)

df$Date <- gsub(df$Date , pattern = "-" , replacement = "/")

df$Date <- as.Date(df$Date,format="%m/%d/%Y")

Answer 3

 > as.Date(parse_date_time(df$Date,c("%m/%d/%Y")))

[1] "1989-01-01" "1989-01-02" "1989-01-03" "1989-01-04" "1989-01-05"
[6] "1989-01-06" "1989-01-07" "1989-01-08" "1989-01-09" "1989-01-10"
[11] "1989-01-11" "1989-01-12" "1989-01-13" "1989-01-14" "1989-01-15"
[16] "1989-01-16" "1989-01-17" "1989-01-18" "1989-01-19" "1989-01-20"
[21] "1989-01-21" "1989-01-22" "1989-01-23" "1989-01-24" "1989-01-25"
[26] "1989-01-26" "1989-01-27" "1989-01-28" "1989-01-29" "1989-01-30"
[31] "1989-01-31"

我有一个CSV文件，其中包含日期列的两种格式（常规和日期）。在使用R时遇到问题

3 个答案:

数据