Question

我的代码从数据库中提取条目并将它们打印成单独的表单，以便我可以使用不同操作的按钮接受或拒绝它们中的每一个。每当我在其中一个表单上执行操作时，它都不会在同一表单上执行操作，而是从数据库中的第一个条目开始按顺序移动。

enter image description here

在上图中，如果我接受第二张表格，它将在第一张表格上执行该功能。

代码：

<?php
} else if ($usertype == 1) { 
ini_set('display_errors',1);
ini_set('display_startup_errors',1);
error_reporting(-1);
$server = "";
$user = "";
$pass = "r=~";
$db = "";
$db3 = "aukwizcq_professors";
$user1 = $_SESSION['username'];
$mysqli  = new Mysqli($server, $user, $pass, $db) or mysqli_error($mysqli);
$mysqli5  = new Mysqli($server, $user, $pass, $db3) or  mysqli_error($mysqli);
$name= $mysqli5->query("SELECT name FROM professor WHERE username= '$user1'")->fetch_object()->name;   //taking name from list of professors that are equal to the userid logged in (if hes a professor, it will show, if not 0)
$overrides = $mysqli->query("SELECT * FROM Overrides WHERE professor= '$name' AND status ='1'"); 
$num_rows = mysqli_num_rows($overrides);



echo "&nbsp;Pending Overrides: " . $num_rows; 
?>
    <?php
    while($row = mysqli_fetch_array($overrides)) { ?>
    <fieldset>
                    <form method="post" action="dbheads.php" name="HF" id="HF" autocomplete="off">

     <?php 
         echo "First Name:&nbsp;&nbsp; " . $row['name'] . "<br />";
         echo "<br />Mid. Name:&nbsp;&nbsp; " . $row['mname'] . "<br />";
         echo "<br />Fam. Name:&nbsp;&nbsp; " . $row['fname'] . "<br />";
         echo "<br />Student ID:&nbsp;&nbsp;&nbsp;&nbsp;" . $row['sid'] . "<br />";
         echo "<br />Scolarship:&nbsp;&nbsp;&nbsp;&nbsp; " . $row['sc'] . "<br />";
         echo "<br />Phone No:&nbsp;&nbsp;&nbsp;&nbsp; " . $row['phone'] . "<br />";
         echo "<br />Email:&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; " . $row['email'] . "<br />";
         echo "<br />Subject:&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; " . $row['subject'] . "<br />";
         echo "<br />Section:&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; " . $row['section'] . "<br />";
         echo "<br />Semester:&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; " . $row['semester'] . "<br />";
                  echo "<br />Professor:&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; " . $row['professor'] . "<br />";  

                  $id = $row['id'];
                  echo "<input type='hidden' name='id' value='$id'>";
             $name = $row['name'];
             echo "<input type='hidden' name='name' value='$name'>";
         $mname = $row['mname'];
         echo "<input type='hidden' name='mname' value='$mname'>";
         $fname = $row['fname'];
         echo "<input type='hidden' name='fname' value='$fname'>";
         $sid = $row['sid'];
         echo "<input type='hidden' name='sid' value='$sid'>";
         $sc = $row['sc'];
         echo "<input type='hidden' name='sc' value='$sc'>";
         $phone = $row['phone'];
         echo "<input type='hidden' name='phone' value='$phone'>";
         $email = $row['email'];                
          echo "<input type='hidden' name='email' value='$email'>";
         $subject = $row['subject'];
                  echo "<input type='hidden' name='subject' value='$subject'>";
         $section = $row['section'];
                  echo "<input type='hidden' name='section' value='$section'>";
         $semester = $row['semester'];
                  echo "<input type='hidden' name='semester' value='$semester'>";
         //$professor = $row['professor'];
                 // echo "<input type='hidden' name='professor' value='$professor'>";



         ?>
<br />
<div>
<label for="comments" accesskey="c">Notes & Comments:</label><br />
<textarea name="comments" id="comments" cols="50" rows="5"></textarea>
<br>
</div>
<br>
<script type="text/javascript">
    function submitForm(action)
    {
        document.getElementById('HF').action = action;
        document.getElementById('HF').submit();
    }
</script>
<input type="button" onclick="submitForm('dbheads.php')" value="Accept" />
<input type="button" onclick="submitForm('dbheads2.php')" value="Deny" />   </form>

    </fieldset>
    <br>
<?php    
}

 ?>

dbheads.php

<?php 
include_once 'includes/db_connect.php';
include_once 'includes/functions.php';
sec_session_start();
?>
<html>

<?php
$mysql_host     = "localhost";
$mysql_username = "";
$mysql_password = "";
$mysql_database = "";
$user = $_SESSION['username'];
  if (login_check($mysqli) == true) : ?>
            <p>Welcome <?php echo htmlentities($user); ?>!</p>
            <?php 
$mysqli  = new Mysqli($mysql_host, $mysql_username, $mysql_password, $mysql_database) or die(mysqli_error());
$status = 2;
$id = $_POST['id'];

$stmt = $mysqli->prepare("UPDATE Overrides SET status=? WHERE id='$id'");
$stmt->bind_param("s", $status);
$stmt->execute();
print 'Error : ('. $mysqli->errno .') '. $mysqli->error;
 echo htmlentities(accepted);
 ?>
         <?php else : ?>
            <p>
                <span class="error">You are not authorized to access this page.</span> Please <a href="index.php">login</a>.
            </p>
        <?php endif; ?>

</html>

请帮忙修理？

Answer 1

您的JS将始终只按照您设置的方式提交上一个<form>中包含的值。

这里最大的问题是您的网页上有多个<form>元素，但没有任何内容可以将您的按钮与特定表单联系起来。

我建议你使用JQuery为每个接受或拒绝发送一个AJAX请求。

以下文章可能有所帮助。

逐个向数据库提交多个表单

1 个答案: