我正在尝试在包含3个片段的活动上实现onBackPressed。我的问题是我在一段时间之后实现了“再次按下退出”但是当单击后退按钮两次时它返回到前一个片段,而不是退出。当调用该片段时(即如果我打开游戏并立即退出它就像一个魅力),就会发生这种情况。我在MainActivity上的onBackPressed方法看起来像这样;
@Override
public void onBackPressed() {
if(getSupportFragmentManager().getBackStackEntryCount()!=0) {
getSupportFragmentManager().popBackStack();
}
this.findViewById(R.id.linearLayout1).setVisibility(View.VISIBLE);
if(mBackPressed + TIME_INTERVAL > System.currentTimeMillis() && getSupportFragmentManager().getBackStackEntryCount()==0){
super.onBackPressed();
System.exit(0);
this.finish();
}
else { Toast.makeText(getBaseContext(), "Press back once more to exit", Toast.LENGTH_SHORT).show(); }
mBackPressed = System.currentTimeMillis();
}
我基本上想检查用户是否在mainActivity布局中,所以我可以使用popBackStack来逃避。任何解决方案都将受到赞赏,如果这还不够,我可以提供更多信息。
谢谢, Bektaş
答案 0 :(得分:1)
如果你真的想退出,请完全忽略后台。使用此代码。
@Override
public void onBackPressed() {
this.findViewById(R.id.linearLayout1).setVisibility(View.VISIBLE);
if(mBackPressed + TIME_INTERVAL > System.currentTimeMillis()){
this.finish();
return;
}
else {
Toast.makeText(getBaseContext(), "Press back once more to exit", Toast.LENGTH_SHORT).show();
}
mBackPressed = System.currentTimeMillis();
}
答案 1 :(得分:0)
我认为您可能会发现此链接很有用 http://developer.android.com/training/implementing-navigation/temporal.html
它说你可以使用这个paturn
添加对堆栈的引用// Works with either the framework FragmentManager or the
// support package FragmentManager (getSupportFragmentManager).
getSupportFragmentManager().beginTransaction()
.add(detailFragment, "detail")
// Add this transaction to the back stack
.addToBackStack()
.commit();
答案 2 :(得分:-1)
@Override
public void onBackPressed() {
int count = getSupportFragmentManager().getBackStackEntryCount();
if (count == 0) {
getSupportFragmentManager().popBackStack(getSupportFragmentManager().getBackStackEntryCount(), getSupportFragmentManager().POP_BACK_STACK_INCLUSIVE);
android.app.AlertDialog.Builder builder = new android.app.AlertDialog.Builder(context);
builder.setCancelable(false);
builder.setMessage("Are you sure you want to exit?")
.setNegativeButton(android.R.string.no, null)
.setPositiveButton(android.R.string.yes, new DialogInterface.OnClickListener() {
public void onClick(DialogInterface arg0, int arg1) {
(Main Activity Name).super.onBackPressed();
}
}).create().show();
} else {
super.onBackPressed();
}
}