Question

我尝试使用以下方法将数据从Android应用程序发送到服务器：

public JSONObject  getJSONFromUrl(String url, List<NameValuePair> params) {

        try{
            // defaultHttpClient
            DefaultHttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost(url);
            for (int i=0; i<params.size(); i++) {
                Log.v("askj",params.get(i).toString());
            }
            httpPost.setEntity(new UrlEncodedFormEntity(params));

            try {
                Log.v("askj","HTTP Entity : " + convertStreamToString(httpPost.getEntity().getContent()));
            }catch (Exception e){
                e.printStackTrace();
            }

            HttpResponse httpResponse = httpClient.execute(httpPost);
            HttpEntity httpEntity = httpResponse.getEntity();
            is = httpEntity.getContent();

        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

        try {
            BufferedReader reader = new BufferedReader(new InputStreamReader(
                    is, "iso-8859-1"), 8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
            is.close();
            json = sb.toString();
            Log.v("askj",json);
            Log.e("JSON", json);
        } catch (Exception e) {
            Log.e("Buffer Error", "Error converting result " + e.toString());
        }

        // try parse the string to a JSON object
        try {
            jObj = new JSONObject(json);
        } catch (JSONException e) {
            Log.e("JSON Parser", "Error parsing data " + e.toString());
        }

        // return JSON String
        return jObj;

    }

我确信我确保我的参数正确，网址很好，但这段代码httpPost.setEntity(new UrlEncodedFormEntity(params));无法正常工作。正在访问的网址没有这些参数。 httpClient.execute(httpPost);只是在没有任何参数的情况下访问初始URL。我怎么解决这个问题？我尝试使用URI而不是setEntity，但我不知道如何一次追加可变数量的参数。

编辑：我使用Postman测试了我的服务，网站可以处理POST请求，因此问题在于JSONParser。

Answer 1

尝试指定这样的编码格式：

httpPost.setEntity(new UrlEncodedFormEntity(params, "utf-8"));

httpPost.setEntity Android问题

1 个答案: