Python:TypeError:'function'对象没有属性'__getitem __'

时间:2015-05-14 18:17:27

标签: python function object typeerror

我是python的新手,我遇到了一些代码问题。我收到了错误

TypeError: 'function' object has no attribute '__getitem__' at line 32

我无法弄清楚发生了什么。从我在互联网上看到的,它意味着将一个函数用作列表,但我无法用我的代码来解决这个问题。我的代码是

#! /usr/local/bin/python


import random


def genFirstGen():
    print "First Generation"
    generation = []
    for chromosomecounter in range(0, 20):
        chromosome = []
        fitness = 0
        for genecounter in range(0, 10):
            chromosome.append(random.randrange(0, 2))
        for genecounter in range(0, 10):
            if (chromosome[genecounter] == 1):
                fitness += 1
        chromosome.append(fitness)
        generation.append(chromosome)
        print gene
    return generation


def FindMostFit(generation):
    failedset = [0,0,0,0,0,0,0,0,0,0,0]
    highestfitness = 0
    mostfit = 0
    fitparents = []
    gene = []
    for fitcounter in range(0, 10):
        for chromosomecounter in range(0, 20):
            chromosome = [generation[chromosomecounter]] #  The error is here.
            fitness  = chromosome[10]
            highestfitness = 0
            if (fitness > highestfitness):
                highestfitness = fitness
                mostfit = chromosomecounter

        fitparents.append(generation[mostfit])
        generation[mostfit] = failedset
    return fitparents


def BreedMostFit(Parents):
    Mother = Parents(random.randrange(0, 10))
    Father = Parents(random.randrange(0, 10))
    child = []
    for genecounter in range(0, 5):
        parentgenetaken = random.randrange(0, 2)
        if (parentgenetaken == 1):
            child.append(Mother[genecounter * 2])
            child.append(Mother[(genecounter * 2) + 1])
        else:
            child.append(Father[genecounter * 2])
            child.append(Father[(genecounter * 2) + 1])
    return child


def Generation2():
    newgeneration = []
    for gencounter in range(0, 20):
        newgeneration.append(BreedMostFit(FindMostFit(genFirstGen)))
    return newgeneration

def GenerationFunction(parentgen):
    generation = []
    for gencounter in range(0, 20):
        generation.append(BreedMostFit(FindMostFit(parentgen)))
    return generation

GenerationFunction(Generation2())

我的智慧结束了。有人可以帮忙吗?谢谢!

2 个答案:

答案 0 :(得分:5)

在第62行,您将genFirstGen函数传递到FindMostFit

newgeneration.append(BreedMostFit(FindMostFit(genFirstGen)))

稍后第32行您将其编入索引。我想你想调用函数并传递其结果。所以用

代替第62行
newgeneration.append(BreedMostFit(FindMostFit(genFirstGen())))

答案 1 :(得分:1)

传递给<% @ship_states.each do |state| %> <%= state.STAXCODE %> <% end %> 的内容是FindMostFit函数本身,而不是来自被调用genFirstGen的输出。

此:

genFirstGen()

应该是这样的:

newgeneration.append(BreedMostFit(FindMostFit(genFirstGen)))