Question

我有一个这样的字符串：

"some string, some $special$ string, some string, some string, some $special$ string,..."

我需要捕获两个$表示法之间的所有单词，并将单词放在<code></code>标记内。上面字符串的结果应该是这样的：

"some string, some <code>special</code> string, some string, some string, some <code>special</code> string,..."

如何通过javascript或jquery执行此操作？

Answer 1

您可以使用替换功能和简单的正则表达式：

modelBuilder.Entity<Booking>()
            .HasRequired(b => b.Report) 
            .WithMany(b => b.Bookings) 
            .HasForeignKey(p => p.Report_Id);

Answer 2

使用foreach fd: find device corresponding to fd call device poll function to setup wait queues (with poll_wait) and to collect its "ready-now" mask while time remaining in timeout and no devices are ready: sleep return from system call (either due to timeout or to ready devices)中的regex，如下所示：

replace

var myStr = "some string, some $special$ string, some string, some string, some $NotSospecial$ string,..."; myStr = myStr.replace(/\$(\w+)\$/g, '<code>$1</code>');：这将转移\$完全匹配
$：捕获组：将匹配任何字符。时间
(\w+)：全局匹配。在第一场比赛后继续
g：来自捕获组的匹配

演示：https://jsfiddle.net/tusharj/o5yn5ast/

Answer 3

使用正则表达式和string.replace的重载，它带有正则表达式和替换函数：

＆＃13;

var re = /\$(.*?)\$/g;
var input = "some string, some $special$ string, some string, some string, some $special$ string,...";
var result = input.replace(re,function(match,g1){
    return "<code>" + g1 + "</code>";
});

alert(result);

＆＃13;

捕获两个特殊字符之间的单词

3 个答案: