我有一个存档表(id,title,author)和一个download_history表(id,id_archive,date)来跟踪每个存档的下载量。现在,我想构建一个报告,以便每周查看下载次数最多的档案。在SQL中做起来很简单,但事情更复杂的是学说,这是我到目前为止所做的:
public function getTopDownloadsLastXDays($limit=100, $days=7)
{
$rsm = new ResultSetMapping();
$rsm->addEntityResult('DownloadHistory', 'd');
$rsm->addMetaResult('d', 'archive', 'archive');
$rsm->addScalarResult('tot', 'tot');
$rsm->addJoinedEntityResult('Archive', 'a', 'd', 'archive');
$rsm->addFieldResult('a', 'author', 'author');
$rsm->addFieldResult('a', 'title', 'title');
$sql = "SELECT
DISTINCT(dh.archive_id),
COUNT(*) as tot,
a.author,
a.title
FROM
download_history dh
INNER JOIN
archive a
ON
dh.archive_id = a.id
WHERE
dh.date >= DATE(NOW()) - INTERVAL :days DAY
GROUP BY
dh.archive_id
LIMIT :limit";
$em = $this->getEntityManager();
$query = $em->createNativeQuery($sql, $rsm);
$query->setParameters(array(
':days' => $days,
':limit' => $limit,
));
$results = $query->getResult();
return $results;
}
实体存在且工作正常。我按照第三个例子: http://doctrine-orm.readthedocs.org/en/latest/reference/native-sql.html#examples。这是我的结果:
array(1) {
[-1]=> array(1) {
["tot"]=> string(1) "1"
}
}
任何想法?感谢
答案 0 :(得分:0)
您将表别名为" dh",但您将别名指定为" d"在构建ResultSetMapping时。