可以向上,向下,向左和向右平移。
识别器1仅处理垂直平底锅,识别器2仅处理水平平底锅。它们都与同一个委托对象链接。
识别器2完全独立于第一个(除了可以选择所描述的4个方向中的一个方向外)。
那么如何防止其中一个与另一个同时执行?
答案 0 :(得分:1)
-(void)initPanGestures{
UIPanGestureRecognizer *panGestureRecognizer1 = [[UIPanGestureRecognizer alloc] initWithTarget:self
action:@selector(handlePan1Gesture:)];
UIPanGestureRecognizer *panGestureRecognizer2 = [[UIPanGestureRecognizer alloc] initWithTarget:self
action:@selector(handlePan2Gesture:)]
}
-(void)handlePan1Gesture:(UIPanGestureRecognizer *)sender{
CGPoint velocity = [sender velocityInView:sender.view];
switch(sender.state) {
case UIGestureRecognizerStateBegan:
if(fabs(velocity.y) > fabs(velocity.x)){
panGestureRecognizer2.enabled=YES;
panGestureRecognizer1.enabled=NO;
}
break;
case UIGestureRecognizerStateCancelled:
panGestureRecognizer1.enabled=YES;
break;
case UIGestureRecognizerStateEnded:{
panGestureRecognizer1.enabled=YES;
}
break;
}
if(velocity.x > 0)
{
NSLog(@"gesture went right");
}
else if(velocity.x < 0)
{
NSLog(@"gesture went left");
}
}
-(void)handlePan2Gesture:(UIPanGestureRecognizer *)sender{
CGPoint velocity = [sender velocityInView:sender.view];
switch(sender.state) {
case UIGestureRecognizerStateBegan:
if(fabs( velocity.x) > fabs(velocity.y)){
panGestureRecognizer2.enabled=NO;
panGestureRecognizer1.enabled=YES;
}
break;
case UIGestureRecognizerStateCancelled:
panGestureRecognizer2.enabled=YES;
break;
case UIGestureRecognizerStateEnded:
panGestureRecognizer2.enabled=YES;
break;
}
if(velocity.y > 0)
{
NSLog(@"gesture went down");
}
else if(velocity.y < 0)
{
NSLog(@"gesture went up");
}
}
另外,对于两个差异手势,你必须实现委托方法并识别手势。例如,我已经同时使用了两个手势和平移手势
#pragma mark - UIGestureRecognizerDelegate methods
- (BOOL)gestureRecognizerShouldBegin:(UIGestureRecognizer *)gestureRecognizer {
return YES;
}
- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer {
if ([panGestureRecognizer1 isEqual:gestureRecognizer]) {
return [panGestureRecognizer2 isEqual:otherGestureRecognizer];
}
if ([panGestureRecognizer2 isEqual:gestureRecognizer]) {
return [panGestureRecognizer1 isEqual:otherGestureRecognizer];
}
return NO;
}