将字符串变量传递给db helper并在查询

时间:2015-05-14 12:42:12

标签: android arrays android-intent get

我创建了两个字符串变量'questionString'和'answerSetId' - 我已经分配给textview的第一个 - 第二个我要传递给我的db helper类:

    public void showNextRandomQuestion3() {

        SQLDatabaseHelper db = new SQLDatabaseHelper(this);

        //get the data from the database
        List<List<String>> listList = db.getAllAnswersByQuestion1();

        //Get the question/text/answer Strings
        List<String> questionStrings = listList.get(0); //question Strings
        List<String> answerSetIds = listList.get(4);

        //Generate random index
        Random r = new Random();
        int rand = Math.abs((r.nextInt() % questionStrings.size()));

        //get answer description for randomly selected question
        String questionString = questionStrings.get(rand);  
        String answerSetId = answerSetIds.get(rand); 

        questionView.setText(questionString);

        }

在我的db helper类中,我想使用这个字符串变量作为我的查询的代码:

public List<List<String>> getAnswers() {

    List<String> array1 = new ArrayList<String>();    
    List<String> array2 = new ArrayList<String>();  

    SQLiteDatabase db = this.getReadableDatabase();

    String selectQuery = "SELECT  * FROM " + TABLE_ANSWERS + "WHERE " + ASID
            + " = " + ??answerSetId??;

   Cursor c = db.rawQuery(selectQuery, null);
   if (c.moveToFirst()) {
    do {

     String textdescr = c.getString(c.getColumnIndex(TDESCR));
     String answersdescr = c.getString(c.getColumnIndex(ADESCR));
     array1.add(textdescr);
     array2.add(answersdescr);;

    } while (c.moveToNext());

 }
   List< List<String> > listArray2 = new ArrayList< List<String> >();
   listArray2.add(array1);
   listArray2.add(array2);

   return listArray2;
}

实现这一目标的最佳方式是什么?

1 个答案:

答案 0 :(得分:0)

要执行SELECT,您可以使用this method

query(String table, String[] columns, String selection, String[] selectionArgs, String groupBy, String having, String orderBy)

而不是原始查询。在你的情况下:

String selection = ASID+"=?";
String selectionArgs[] = new String[]{String.valueOf(answerSetId)};
Cursor c = db.query(TABLE_ANSWERS, null, selection, selectionArgs, null, null, null);

您还可以选择一些特定的列,将列名称作为第二个参数传递(insted为null)。此外,您可以替换示例中的最后三个空值,以添加GROUP BYHAVINGORDER BY子句。

例如,在您的查询中,您只对两列TDESCR和ADESCR感兴趣。所以你可以使用这个查询:

String[] columns = new String[]{TDESCR, ADESCR};
String selection = ASID+"=?";
String[] selectionArgs = new String[]{String.valueOf(answerSetId)};
Cursor c = db.query(TABLE_ANSWERS, columns, selection, selectionArgs, null, null, null);

还有很多其他覆盖方法查询。请查看文档here

但是,如果您愿意,可以通过以下方式执行原始查询:

String queryString = "SELECT * FROM " + TABLE_ANSWERS +
    " WHERE "+ASID+"=?";
String[] selectionArgs = new String[]{String.valueOf(answerSetId)};
sqLiteDatabase.rawQuery(queryString, selectionArgs);