Question

我正在尝试在Swift for OS X中创建一个代码，其中一个功能是搜索Address Book条目。下面的代码可以找到条目，并且可以在一个搜索词中正常工作，让人们说出名字John。但是，如果使用第二个搜索词：即名字和姓氏＆＃34; John Doe＆＃34; （空格分隔）它返回名称的所有匹配＆＃34; John＆＃34;和姓氏的所有比赛＆＃34; Doe＆＃34;。

如何强制代码搜索字符串的其余部分，即仅在已经输入的sting的第一部分匹配的地址簿条目中的姓氏，即姓名？

搜索John Dow我只想获得John Doe的地址簿条目，而不是John Doe，John Roe，John Moe，Andrew Doe和＃34;等？

抱歉我的英文

let addressBook = ABAddressBook.sharedAddressBook()
var dataArray:[NSDictionary] = [["personCell": "", "emailCell": ""]]
var foundPeople = 0
var personNo = 0 

var searchString = "John Doe"


func searchAB() -> NSArray {

    var mySearchWord = searchString.componentsSeparatedByString(" ")

    for word in mySearchWord {

        var searchWord = mySearchWord.removeAtIndex(mySearchWord.endIndex.predecessor())
        let comparison: ABSearchConjunction = CFIndex(kABContainsSubStringCaseInsensitive.value)
        let firstNameSearch = ABPerson.searchElementForProperty(kABFirstNameProperty,
            label: nil,
            key: nil,
            value: searchWord,
            comparison: comparison)

        let middleNameSearch = ABPerson.searchElementForProperty(kABMiddleNameProperty,
            label: nil,
            key: nil,
            value: searchWord,
            comparison: comparison)

        let lastNameSearch = ABPerson.searchElementForProperty(kABLastNameProperty,
            label: nil,
            key: nil,
            value: searchWord,
            comparison: comparison)


        let comparisons = [firstNameSearch, middleNameSearch, lastNameSearch]
        let orComparison = ABSearchElement(forConjunction: CFIndex(kABSearchOr.value), children: comparisons)
        let found = addressBook.recordsMatchingSearchElement(orComparison) as! [ABRecord]


    for person in found {

        let firstName = person.valueForProperty(kABFirstNameProperty) as! String? ?? ""
        let middleName = person.valueForProperty(kABMiddleNameProperty) as! String? ?? ""
        let lastName = person.valueForProperty(kABLastNameProperty) as! String? ?? ""
        let emailsProperty = person.valueForProperty(kABEmailProperty) as! ABMultiValue?


        foundPeople++

       var tmpFirstName = firstName
       var booleanFName = tmpFirstName.isEqualToString(firstName)

        if let emails = emailsProperty {

            for i in 0..<emails.count() {

                let email = emails.valueAtIndex(i) as! String
                var emailType =  ABLocalizedPropertyOrLabel(emails.labelAtIndex(i)) //telefono numerio tipas
                if (booleanFName) {
                     personNo++
                    if (personNo == 1) { // first person

                        dataArray = [["personCell": "\(firstName) \(middleName) \(lastName)", "emailCell": "\(email) (\(emailType))"]]
                    } else {
                        dataArray += [["personCell": "\(firstName) \(middleName) \(lastName)", "emailCell": "\(email) (\(emailType))"]]

                    } // end if personNo
                    println("\n• \(personNo) \(firstName) \(middleName) \(lastName)")
                    println("\t\t\(email) (\(emailType))")

                    booleanFName = false
                } else {
                    dataArray += [["emailCell": "\(email) (\(emailType))"]]
                    println("\t\t\(email) (\(emailType))")
                } // end booleanFName
            } // end for i
          } // end if let emails
        } // end for person in found
     } // end for word

    return dataArray;
  } // end func

如何使用Swift for OS X搜索名称和姓氏，避免重复结果

0 个答案: