Question

我有一个日志文件，其中包含正常STDOUT中的xml，如下所示：

2015-05-06 04:07:37.386 [INFO]Process:102 - Application submitted Successfully ==== 1
<APPLICATION><FirstName>Test</FirstName><StudentSSN>123456789</StudentSSN><Address>123 Test Street</Address><ParentSSN>123456780</ParentSSN><APPLICATIONID>2</APPLICATIONID></APPLICATION>
2015-05-06 04:07:39.386 [INFO] Process:103 - Application completed Successfully ==== 1
2015-05-06 04:07:37.386 [INFO]Process:104 - Application submitted Successfully ==== 1
<APPLICATION><FirstName>Test2</FirstName><StudentSSN>323456789</StudentSSN><Address>234 Test Street</Address><ParentSSN>123456780</ParentSSN><APPLICATIONID>2</APPLICATIONID></APPLICATION>
2015-05-06 04:07:39.386 [INFO] Process:105 - Application completed Successfully ==== 1

我的目标是解析此文件并用***替换任何出现的个人数据。因此，上述脚本之后的所需输出应为：

2015-05-06 04:07:37.386 [INFO]Process:102 - Application submitted Successfully ==== 1
<APPLICATION><FirstName>***</FirstName><StudentSSN>***</StudentSSN><Address>*******</Address><ParentSSN>*********</ParentSSN>   <APPLICATIONID>2</APPLICATIONID></APPLICATION>
2015-05-06 04:07:39.386 [INFO] Process:103 - Application completed Successfully ==== 1
2015-05-06 04:07:37.386 [INFO]Process:104 - Application submitted Successfully ==== 1
<APPLICATION><FirstName>***</FirstName><StudentSSN>*********</StudentSSN><Address>*****</Address><ParentSSN>*********</ParentSSN>   <APPLICATIONID>2</APPLICATIONID></APPLICATION>
2015-05-06 04:07:39.386 [INFO] Process:105 - Application completed Successfully ==== 1

提前谢谢。

Answer 1

使用此内容创建文件foo.sed：

s|<FirstName>[^<]*</FirstName>|<FirstName>***</FirstName>|
s|<StudentSSN>[^<]*</StudentSSN>|<StudentSSN>***</StudentSSN>|
s|<Address>[^<]*</Address>|<Address>***</Address>|
s|<ParentSSN>[^<]*</ParentSSN>|<ParentSSN>***</ParentSSN>|

尝试使用GNU sed：

sed -f foo.sed log_file > new_file

或编辑文件＆＃34;到位＆＃34;：

sed -i -f foo.sed log_file

使用嵌入式xml解析和操作日志文件

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