Question

我正在尝试从dp获取更新记录的值。让我简要介绍一下 -

1.我有两个while循环，一个用于显示数据库中的记录，另一个用于在编辑操作后获取。

2.编辑了1个字段之后，记录应该在数据库中更新[我已经在db中成功更新了记录/记录]但问题是它在数据库中成功更新[因为我确实检查了我的数据库，因为我更新记录]但不显示更新记录的记录。我认为它不会进入更新查询的while循环。

请提出一些解决方案。

if(isset($_POST['recruiter_s_by_code'])
{
 //some code here...the query here is being a sucesss
 //SELECT STATEMENT here..
}
if(isset($_POST['recruiter_s_by_mail'])
{
 //some code here...the query here is being a sucesss
 //SELECT STATEMENT here..
}
if(isset($_POST['recruiter_s_by_name'])
{
 //some code here...the query here is being a sucesss
 //SELECT STATEMENT here..
}

if(isset($_POST['recruiter_s_by_code']) || isset($_POST['recruiter_s_by_name']) || isset($_POST['recruiter_s_by_mail'])) 
{
 $result=mysql_query($sql);
 echo "in result"
 while($row=mysql_fetch_array($result))
 {
    $viewrecruiter0=$row['recruiter_did'];
    $viewrecruiter1=$row['recruiter_name'];
    $viewrecruiter2=$row['recruiter_mail'];

 } 
 }

 else
 {
    if(isset($_GET['var']))
    {
      $id1=$_GET['var'];
      echo $id1;
    }
    //$query1=UPDATE .......SET......WHERE...   ->the update too is a success for me.
$res=mysql_query($query1);
while($row=mysql_fetch_array($res)) 
{       
 $viewrecruiter00=$row['recruiter_did']; //by code
 $viewrecruiter01=$row['recruiter_name'];
 $viewrecruiter02=$row['recruiter_mail'];
}
}
?>

UPDATE查询运行成功，但UPDATE点击后不显示记录。仅显示标签，但不显示值。

Answer 1

听起来您正在一次编辑/更新一条记录，因此请执行更新，然后在同一记录上运行选择。

//$query1=UPDATE .......SET......WHERE...   ->the update too is a success for me.
$res=mysql_query($query1);
//$query1='select yada yada yada from table where SAME CONDITIONS';
$res=mysql_query($query1);
while($row=mysql_fetch_array($res)) {

如果在查询中使用$id1，则需要将mysql_real_escape_string放入I have anothere backup where I have used mysqli。当你说$result = mysql_query("INSERT INTO `test1`(survey_no,lastname) VALUES ('$survey_no','$lastname')"); $result1 = mysql_query("INSERT INTO `test2`(survey_no) VALUES ('$survey_no')");你应该尽可能使用mysqli而不是mysql_时，我也不清楚你的意思。

mysql_fetch_array出错。无法通过while循环获取记录

1 个答案: