如何在没有插入文件的表元素的情况下创建csv文件

Question

我有这个代码完全正常，但它也打印出表格元素。我不知道如何解决它。感谢

<?php
    // output headers so that the file is downloaded rather than displayed
    header('Content-Type: text/csv; charset=utf-8');
    header('Content-Disposition: attachment; filename=deferred_doc.csv');

    // create a file pointer connected to the output stream
    $output = fopen('php://output', 'w');

    // output the column headings
    fputcsv($output, array('APP NUMBER', 'SPOC ASSIGNED', 'BORROWER NAME', 'APP_FINISH_DATE','DEVELOPER & PROJECT', 'COLLATERAL ADDRESS DETAILS' ,'ORIGINAL_DEADLINE', 'DEFERRED TYPE','DEFERRED_DOCUMENT','SPOC REMARKS', 'JUW-MA REMARKS', 'COSU REMARKS','FILE LOCATION','SMU NOTES','DATE COMPLETED','SUBMITTED/PENDING','ID'));

    // fetch the data
    mysql_connect('xxxx', 'xxxx', 'xxx');
    mysql_select_db('export_workflow');
    $rows = mysql_query('SELECT * FROM COLLATERAL_MANAGEMENT');

    // loop over the rows, outputting them
    while ($row = mysql_fetch_assoc($rows)) fputcsv($output, $row);
    ?>

csv打印出像这个

这样的表格元素

Answer 1

我使用my_sql做了错误的代码，应该使用my_sqli从数据库中获取数据