我正在学习Django,我偶然发现了一些我需要帮助的东西:
forms.py
class UserForm(forms.ModelForm):
password1 = forms.CharField(widget=forms.PasswordInput())
password2 = forms.CharField(widget=forms.PasswordInput())
class Meta:
model = User
fields = ('username', 'email', 'password1','password2')
def password_matched(self):
if self.data['password1'] != self.data['password2']:
self.errors['password'] = 'Passwords do not match'
return False
else:
return True
def is_valid(self):
valid = super(UserForm,self).is_valid()
password_matched = self.password_matched()
if valid and password_matched:
return True
else:
return False
views.py
def register(request):
#blah...
user.set_password(user.password)
# user.set_password(user.password1) doesn't work ! WHY!?
基本上,我正在检查是否pw1 == pw2
,
检查后,我希望将用户密码设置为password1
我最初使用了行user.set_password(user.password1)
,但它抱怨User对象没有password1
,但是当我使用password
时它就有效。
为什么?感谢。
答案 0 :(得分:8)
理想情况下,您应该使用clean
方法,而不要触及is_valid
方法。
这样的事情:
def clean(self):
cd = self.cleaned_data
password1 = cd.get("password1")
password2 = cd.get("password2")
if password1 != password2:
#Or you might want to tie this validation to the password1 field
raise ValidationError("Passwords did not match")
return cd
现在,在视图中,
def register(request):
#blah...
form = UserForm(request.POST or None)
if request.method == "POST":
if form.is_valid(): #This would call the clean method for you
user = User.objects.create(...)
user.set_password(form.cleaned_data.get("password1"))
user.save()
else: #Form is invalid
print form.errors #You have the error list here.