Question

public class HomepageActivity extends ActionBarActivity {

protected List<ParseObject> mStatus;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_homepage);

    Parse.initialize(this, "dcAMNT7HVOmOw0JDMelkg5UDr388O3xSgICiSK3N", "1aHIAldsUScxlbkWGkoyvHoHWM9YEtpTb6QIijrb");

    ParseUser currentUser = ParseUser.getCurrentUser();
    if (currentUser != null) {
        // show user the homepage status
        ParseQuery<ParseObject> query = ParseQuery.getQuery("Status");
        query.whereEqualTo("playerName", "Dan Stemkoski");
        query.findInBackground(new FindCallback<ParseObject>() {
            public void done(List<ParseObject> status, ParseException e) {
                if (e == null) {
                    //success
                    mStatus = status;
                    StatusAdapter adapter = new     StatusAdapter(getListView().getContext(),mStatus);
                    setListadapter(adapter);
                } else {
                    //there was a problem, Alert user

                }
            }
        });

我被困了，因为我需要一个列表活动，我需要使用List适配器，但我使用的是我的HomepageActiviy扩展ActionBarActivity。唯一可行的方法是，如果我将扩展名更改为List活动，但是当我按下s4上的左键时，我的操作栏上的设置将不会仅显示在按钮的顶部。

Answer 1

为什么会使事情变得复杂，您可以将其保留extends ActionBarActivity并在xml布局文件中使用ListView小部件。听起来很简单。

另外：您不能使用getListView和setListadapter，除非您正在延长ListActivity，在您的情况下，您无法继续

提示：

http://developer.android.com/guide/topics/ui/layout/listview.html

Custom Adapter for List View

http://androidexample.com/Create_A_Simple_Listview_-_Android_Example/index.php?view=article_discription&aid=65&aaid=90

或只是google与listview相关的任何内容

Answer 2

也许这会有所帮助

public class HomepageActivity extends ActionBarActivity {
    private ListView lv; // Add a reference to your listview
    protected List<ParseObject> mStatus;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_homepage);
        lv = (ListView) findViewById(R.id.list); // Initialize your listview by pointing it to the correct listview in the layout file
        Parse.initialize(this, "dcAMNT7HVOmOw0JDMelkg5UDr388O3xSgICiSK3N", "1aHIAldsUScxlbkWGkoyvHoHWM9YEtpTb6QIijrb");

        ParseUser currentUser = ParseUser.getCurrentUser();
        if (currentUser != null) {
            // show user the homepage status
            ParseQuery<ParseObject> query = ParseQuery.getQuery("Status");
            query.whereEqualTo("playerName", "Dan Stemkoski");
            query.findInBackground(new FindCallback<ParseObject>() {
                public void done(List<ParseObject> status, ParseException e) {
                    if (e == null) {
                        //success
                        mStatus = status;
                        StatusAdapter adapter = new StatusAdapter(HomepageActivity.this ,mStatus); // Use the activity's context as the first parameter
                        lv.setAdapter(adapter); // Populate you listview here
                    } else {
                        //there was a problem, Alert user

                    }
                }
            });

确保activity_homepage布局中的<ListView>标记具有这样的id属性 android:id="@+id/list"

一切顺利：）

当我的HomepageActivty扩展ActionBarActivity时，我无法使用List Activity

2 个答案: