Question

我使用ActiveJDBC和Oracle 11g DB。当我使用saveIt时，我得到java.sql.Exception。当我得到它的实例或列表时，一切都好。我做错了什么？

Exception in thread "main" org.javalite.activejdbc.DBException: java.sql.SQLException: Invalid argument
зове, query: INSERT INTO dept (DEPTNO, DNAME, LOC) VALUES (?, ?, ?), params: 45, sdfa, fdg
        at oracle.jdbc.driver.AutoKeyInfo.getNewSql(AutoKeyInfo.java:187)
        at oracle.jdbc.driver.PhysicalConnection.prepareStatement(PhysicalConnection.java:5704)
        at org.javalite.activejdbc.DB.execInsert(DB.java:598)
        at org.javalite.activejdbc.Model.insert(Model.java:2698)
        at org.javalite.activejdbc.Model.save(Model.java:2597)
        at org.javalite.activejdbc.Model.saveIt(Model.java:2524)
        at JavaHomeTask.Dept.addPersistence(Dept.java:72)
        at JavaHomeTask.App.addRow(App.java:103)
        at JavaHomeTask.App.main(App.java:50)
Caused by: java.sql.SQLException: Invalid argument
        ... 9 more

这是我的代码：

public void addPersistence() throws IOException {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        Dept d = new Dept();
        String value;
        for (String s : getAttributesNames()) {
            System.out.println("Enter " + s + " and press Enter button:");
            value = reader.readLine();
            d.set(s, value);
        }
        d.saveIt();

    }

public List<String> getAttributesNames() {
        return Arrays.asList("DEPTNO", "DNAME", "LOC");
    }

Answer 1

问题的原因是ActiveJDBC使用id列作为表中的Primari Key来识别应该使用哪个操作 - INSERT或UPDATE。如果表没有这样的列，程序员应该使用@IdName（“nameOfColumn”）注释手动指定PK。您可以找到更多信息here

使用ActiveJDBC时出现sqlException

1 个答案: