我想知道如何在PHP中运行GET命令... 这是我的代码:
<?php
$msg = $_GET['msg'];
echo "$msg test";
if (!function_exists("ssh2_connect")) die("function ssh2_connect doesn't exist");
if(!($con = ssh2_connect("ip", 22))){
echo "fail: unable to establish connection\n";
} else {
// try to authenticate with username root, password secretpassword
if(!ssh2_auth_password($con, "root", "password")) {
echo "fail: unable to authenticate\n";
} else {
// allright, we're in!
echo "okay: logged in...\n";
// execute a command
if (!($stream = ssh2_exec($con, 'wall echo $msg'))) {
echo "fail: unable to execute command\n";
} else {
// collect returning data from command
stream_set_blocking($stream, true);
$data = "";
while ($buf = fread($stream,4096)) {
$data .= $buf;
}
fclose($stream);
}
}
}
?>
所以,它不会挂在我所说的内容中?msg = ...它只是写空白,但当我回显$ msg(就像我在代码顶部做的那样)它正常写,你们知道在哪里吗?问题?我已经尝试过“echo $ msg”和“echo $ msh”,但是同样的事情......谢谢和最好的问候!
答案 0 :(得分:1)
将GET变量传递给ssh2_exec()
可能是一个巨大的安全问题。但忽略这一点,单引号忽略变量 - 你需要双引号。
换句话说:改变这个
if (!($stream = ssh2_exec($con, 'wall echo $msg'))) {
到这个
if (!($stream = ssh2_exec($con, "wall echo $msg"))) {
但是,我怀疑您正在尝试使用echo
作为PHP构造,而您只对$msg
变量感兴趣。在这种情况下,你可以做到
if (!($stream = ssh2_exec($con, "wall $msg"))) {
或
if (!($stream = ssh2_exec($con, 'wall ' . $msg))) {