如何将ctypes.POINTER传递给boost.python

Question

我有以下代码：

old_lib.h：

struct DUMMY
{
    // some members
};

module.cpp：

#include <boost/python.hpp>
#include "old_lib.h"

namespace py = boost::python;

void foo(py::object const& p)
{
    // How to get rid of ctypes.addressof()?
    static py::object ctypes_addressof = py::import("ctypes").attr("addressof");
    DUMMY *ptr = *reinterpret_cast<DUMMY**>(uintptr_t(py::extract<uintptr_t>(ctypes_addressof(p))));
}

BOOST_PYTHON_MODULE(module)
{
    py::def("foo", &foo, args("p"));
}

old_python.py：

import ctypes
class DUMMY(ctypes.Structure):
    _pack_ = 4
PDUMMY = POINTER(DUMMY)
# some old stuff using PDUMMY

new_python.py：

from module import foo
from old_python import PDUMMY
x = PDUMMY()
# some calls to old python (e.g. initialization of x)
foo(x)

假设python代码是不可更改的。

如何摆脱ctypes.addressof（）？我想，调用它比仅提取值更昂贵，特别是在频繁调用foo（）的情况下。 UPD：换句话说，如何在不使用ctypes.addressof（）的情况下获取ctypes._Pointer实例的值？

有没有办法将参数类型指定为'foo（PDUMMY p）'并将转换器从ctypes.POINTER写入PDUMMY？