Question

我想知道如何正确显示标签上列表中的所有对象。

{
class HighScore
{
    public string name;
    public int points;

    public HighScore(string N, int P)
    {
        this.name = N;
        this.points = P;
    }


}

private void Form1_Load(object sender, EventArgs e)
    {
        List<HighScore> score = new List<HighScore>();
        score.Add(new HighScore("Paul", 20));
        score.Add(new HighScore("Robert", 30));
        score.Add(new HighScore("John", 25));
        score.Add(new HighScore("Michael", 300));

        foreach(HighScore per in score)
        {
            label1.Text = per.name + "  " + per.points;
        }
    }
}

我尝试使用foreach循环使标签显示列表中的所有值，但它只显示一个值，而不是所有值。如何在标签上正确显示此列表？

Answer 1

首先，您使用=，因此在每次迭代时，您都会替换label1.Text值作为解决方案，您可以简单地使用+=运算符，因此将附加到label1.Text值。

另一种方式：类中的override ToString方法，例如

public override string ToString(){
    return per.name + "  " + per.points;
}

并使用它label1.Text += per.ToString();
或者string.Join喜欢

private void Form1_Load(object sender, EventArgs e)
{
    List<HighScore> score = new List<HighScore>();
    score.Add(new HighScore("Paul", 20));
    score.Add(new HighScore("Robert", 30));
    score.Add(new HighScore("John", 25));
    score.Add(new HighScore("Michael", 300));

    label1.Text = string.Join(",", score);
}

如果您无法覆盖ToString，则可以使用下一个linq Select

private void Form1_Load(object sender, EventArgs e)
{
    List<HighScore> score = new List<HighScore>();
    score.Add(new HighScore("Paul", 20));
    score.Add(new HighScore("Robert", 30));
    score.Add(new HighScore("John", 25));
    score.Add(new HighScore("Michael", 300));

    label1.Text = string.Join(",", score.Select(per=>per.name + "  " + per.points));
}

Answer 2

你的解决方案应该像这样“重新制定”：

private void Form1_Load(object sender, EventArgs e)
        {
            List<HighScore> score = new List<HighScore>();
            score.Add(new HighScore("Paul", 20));
            score.Add(new HighScore("Robert", 30));
            score.Add(new HighScore("John", 25));
            score.Add(new HighScore("Michael", 300));
            StringBuilder labelResult = new StringBuilder();
            foreach(HighScore per in score)
            {
                labelResult.Apend(per.name + "  " + per.points+"\n");
            }
            labe1.Text = labelResult.ToString();
        }

显示标签中的所有对象值（WFA）

2 个答案: