Question

基本上，我有这个while循环，它检索按下按钮的坐标（这是一个棋子）并通过循环查看是否可以进行移动。

然而，同一棋子的坐标不断被馈送，所以如果棋子没有可用的动作，同样的信息会一直反复显示，直到按下不同的按钮，同样的事情发生了再次，如果那件没有动作。如果每次单击一个片段，我将如何仅打印相同的消息？

我尝试使用do while循环，其中while循环中的条件仅检查如果坐标的值与正在输入的值不同，按钮是否可用。但这没有区别？

        while(!correctMove){
            do{
                fromXCo = s.getFromXInt();
                fromYCo = s.getFromYInt();
                toXCo = s.getToXInt();
                toYCo = s.getToYInt();

                    p = board.getPiece(fromXCo, fromYCo);

                    //checks if occupied co-ordinate, if not goes back out the loop and asks again.
                    if (!board.occupied(fromXCo, fromYCo)){
                        System.out.println("Please choose occupied co-ordinates \n");
                        correctMove = false;
                    }

                    //checks if the colour is the same as the player's. If not, asks for co-ordinates again.
                    if (p.getColour() != getPieces().getColour()){
                        System.out.println("Please move your own pieces \n");
                        correctMove = false;
                    }

                    //tells player their selected piece
                    System.out.println("Your selected piece is " + p.getChar());

                    //looks through available moves for piece
                    moves = p.availableMoves();

                    //if no moves available, asks for new co-ordinates.
                    if (moves == null){
                        System.out.println("No moves available for this piece \n");
                        correctMove = false;
                    }
                    else {

                        Move found = null;

                        for( Move m : moves){
                            //checks if move can be done
                            if (m.ToX() == toXCo && m.ToY() == toYCo){
                                //if move is allowed- exit loop
                                found = m; 

                                correctMove = true;

                            }
                        }

                        if (found == null) {
                            //if move can't be, ask for new co-ordinates
                            System.out.println("This move is not legal \n");
                            correctMove = false;

                        }   
                    }
                }while(fromXCo != s.getFromXInt() && fromYCo != s.getFromYInt() && toXCo != s.getToXInt() && toYCo != s.getToYInt());
            }

Answer 1

如果我理解正确while的目的是如果没有选择合法移动的合法作品，用户可以重复选择。您不需要有两个while循环（内部while似乎只是作为if）。我就是这样做的（伪代码）：

correctMove = false;
While(!correctMove) {
    square = inputNewSquare();
    if(isEmpty(square))
        "click on a piece"
    else if(pieceHasRightColor(square))
        "you can only move your own piece"
    else if(!pieceHasMove(square))
        "this piece has no legal move"
    else {
        //move(s) found, do stuff
        correctMove = true;
    }
}

如果值相同，则停止while循环 - Java

1 个答案: