Question

我试图在Spring 3.0中通过AJAX加载数据，但AJAX URL无法在Spring中找到控制器，我也不知道如何解决这个问题。

我知道在服务器启动时它会查找URL并获取数据但是在这里我可以在春季正确地创建注释并且我已经在网上搜索了很多但没有成功。

我的Java课程：

package springactiontest;

import java.util.List;

import javax.servlet.http.HttpSession;

import org.json.simple.JSONArray;
import org.json.simple.JSONObject;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import org.springframework.stereotype.Controller;
import org.springframework.ui.ModelMap;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;

import Dao.dao;


@Controller
//@RequestMapping("/employee")
public class mainclass {

    @RequestMapping(value="/AddUser",method=RequestMethod.GET)

public @ResponseBody static String data(ModelMap model, HttpSession session) {

        System.err.println("err ocured");

          ApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");

          setvalueclass studentJDBCTemplate =(setvalueclass)context.getBean("actionclass");

          System.out.println("------list district--------" );

        JSONArray newtest=new JSONArray();

          List<dao> students = studentJDBCTemplate.listStudents();
          for (dao record : students) 
          {

             JSONObject ob=new JSONObject();
             System.out.print("ID test: " + record.getDistrict());
             ob.put("distrct", record.getDistrict());
             newtest.add(ob);
          }

          System.err.println("error");


          String res=newtest.toString();

          System.err.println("error"+res);

        return res;

     }

}
Jsp:
$("document").ready(function () {

        alert("distrcict");

        dist_pop();

});

function dist_pop() {

var urlService="http://tamilnilam:8080/SpringTest";
        $.ajax({
        url: urlService +'/AddUser',
        type: 'GET',
        dataType: 'jsonp',

        contentType: "application/json",
          success: function (data) {

            alert("sucess")          

        },
        error: function (jqXHR, exception) {

            alert("Error Occured in dist pop");

        }

    });

}

的applicationContext.xml：

<?xml version="1.0" encoding="UTF-8"?>       
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/context
    http://www.springframework.org/schema/context/spring-context-3.0.xsd">  

   <context:component-scan base-package="springactiontest.setvalueclass"/>


   <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
      <property name="driverClassName" value="org.postgresql.Driver"/>
      <property name="url" value="jdbc:postgresql://10.163.2.165:5434/land_rural"/>
      <property name="username" value="postgres"/>
      <property name="password" value="postgres"/>
   </bean> 


   <bean id="actionclass" class="springactiontest.setvalueclass">
      <property name="dataSource"  ref="dataSource" />    
   </bean>
</beans>

Answer 1

看起来缺少component-scan，它有助于Spring检测并实例化使用@Component，@Service，@Repository，@Controller注释的Spring bean， @Endpoint等

<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/context
    http://www.springframework.org/schema/context/spring-context-3.0.xsd">

    <context:component-scan base-package="com.your.controller.package" />

    // Rest of the bean defiantions
</beans>

供参考：Spring MVC tutorial

无法在AJAX的Spring注释中找到控制器

1 个答案: