Question

我正在尝试编写一个RPG游戏，并坚持如何使用一个唯一ID来调用项目，怪物，任务等来获取所有数据。这主要基于this Code Review question中的最佳答案。

我不想将所有数据传递给Item类，而是调用一个方法或函数，该方法或函数包含所有项目的字典，然后根据这些项目将数据传递给Item一个唯一的ID。

我目前拥有的相关代码如下（所有代码都可以找到here）：

inventory.add_item(Item(ListItem.list(1))) #The 1 is a placeholder to specifically get the sword.

class Inventory(object):
    def __init__(self):
        self.items = {}

    def add_item(self, item):
        self.items[item.name] = item

class Item(object):
    def __init__(self, name, attack, armor, cost, quantity, description):
        self.name = name
        self.attack = attack
        self.armor = armor
        self.cost = cost
        self.quantity = quantity
        self.description = description


class ListItem(object):
# This is a database to hold all the games loot/items
    def __init__(self):
    # What goes here? 

    def list(self, itemid):
    # Probably don't even need this here? Can it go under __init__?
        all_items = {
            1: {"name": "Sword", "desc": "A rusty looking sword", "dmg": 5,         "arm": 1, "val": 10},

            }
        return list(all_items[itemid].values())

Answer 1

我得到了它的工作，但也许不是最有效的方式如下：

1）删除了ListItem类

2）将字典添加到主方法

3）将变量iid（项目ID）设置为房间中项目的值

4）将项目的每个值传递给Item类

但这限制了我每个位置的一个项目。

location = {
    2: {"name": "Cave - Upper area",
        "description": "Placeholder",
        "west": 1,
        "south": 4,
        "item": "sword",
        "iid": 1},

all_items = {
    1: {"name": "Sword", "dmg": 5, "arm": 1, "val": 10, "desc": "A rusty looking sword"},
    100: {"name": "Beer", "desc": "A foaming mug of ale", "dmg": 1, "arm": 1, "val": 1}
    }

elif move[0] == "get":
    if "iid" in location[currentLocation] and move[1] in location[currentLocation]["item"]:
        iid = location[currentLocation]["iid"]
        inventory.add_item(Item(all_items[iid]["name"], all_items[iid]["dmg"], all_items[iid]["arm"], all_items[iid]["val"], all_items[iid]["desc"]))
        print("%s added to inventory!\n" % all_items[iid]["name"])
        del location[currentLocation]["item"]
    else:
        print("\nThere is no %s here!\n" % move[1])

使用唯一ID（python）将项目添加到库存中

1 个答案: