Question

我这是一个查询

SELECT * FROM user_state_logs WHERE user_state_logs.user_id = 1
AND created_at BETWEEN '2015-05-03 11:06:05' AND '2015-05-13 11:06:05'

返回此

user_id   state   duration
1         call    10
1         call    20
1         wait    30
1         call    10
1         wait    20

我想回复此

user_id   state   duration
1         call    40
1         wait    50

我尝试添加GROUP BY user_state_logs.state

但是我收到了这个错误

错误：列“user_state_logs.user_id”必须出现在GROUP BY中子句或用于聚合函数

所以有两个问题：

为什么我会收到此错误？

我怎样才能让查询以第二种格式返回数据？

Answer 1

尝试这样做：

SELECT user_state_logs.state, user_state_logs.user_id, sum(user_state_logs.duration)  as duration
FROM user_state_logs 
WHERE user_state_logs.user_id = 1
AND created_at BETWEEN '2015-05-03 11:06:05' AND '2015-05-13 11:06:05'
GROUP BY user_state_logs.state, user_state_logs.user_id

Answer 2

您应该按user_id和state分组：

SELECT user_id, state, sum(duration)
WHERE user_state_logs.user_id = 1
   AND created_at BETWEEN '2015-05-03 11:06:05' AND '2015-05-13 11:06:05'
GROUP BY user_id, state

Answer 3

您收到错误，因为在使用group by语句时定义选择列表。试试这个：

SELECT user_id, state, duration FROM user_state_logs 
WHERE user_state_logs.user_id = 1
AND created_at BETWEEN '2015-05-03 11:06:05' AND '2015-05-13 11:06:05'
GROUP BY user_id, state, duration

或

SELECT user_id, state, max(duration) FROM user_state_logs 
WHERE user_state_logs.user_id = 1
AND created_at BETWEEN '2015-05-03 11:06:05' AND '2015-05-13 11:06:05'
GROUP BY user_id, state

按一列分组并另外一列

3 个答案: