Question

我希望通过 Parse.com 和 Cloud Code 或 iOS代码来避免重复。这是我的数据库类： Screenshot

我想当“来自”userId已经发送到“到”userId时，它不会发送第二个friendRequest。

这是我的iOS代码：

PFUser *selectedUser = [self.allUsers objectAtIndex:indexPath.row];
//request them
PFObject *friendRequest = [PFObject objectWithClassName:@"FriendRequest"];
friendRequest[@"from"] = self.currentUser;
friendRequest[@"fromUsername"] = [[PFUser currentUser] objectForKey:@"username"];
//selected user is the user at the cell that was selected
friendRequest[@"to"] = selectedUser;
// set the initial status to pending
friendRequest[@"status"] = @"pending";
[friendRequest saveInBackgroundWithBlock:^(BOOL succeeded, NSError *error) {

    if (succeeded) {


        UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Sent !" message:@"Friend request sent" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil, nil];
        [alert show];



    } else {

        // error occurred
    }
}];

Answer 1

嗨如果您已发送好友请求或来自＆＃34; CurrentUser＆＃34;您可以执行以下操作。到＆＃34; SelectedUser＆＃34;：

-(void)fetchfriendrequestAndSave{

    PFUser *selectedUser = [self.allUsers objectAtIndex:indexPath.row];
    //request them
    PFObject *friendRequest = [PFObject objectWithClassName:@"FriendRequest"];
    friendRequest[@"from"] = self.currentUser;
    friendRequest[@"fromUsername"] = [[PFUser currentUser] objectForKey:@"username"];
    //selected user is the user at the cell that was selected
    friendRequest[@"to"] = selectedUser;
    // set the initial status to pending
    friendRequest[@"status"] = @"pending";

    PFQuery*query = [PFQuery queryWithClassName:@"FriendRequest"];
    [query whereKey:@"from" equalTo:self.currentuser];
    [query whereKey:@"to" equalTo: selectedUser];
    [query findObjectsInBackgroundWithBlock:^(NSArray*FriendRequestArray, NSError*error){

        if(!error){

            NSArray*temp = [NSArray arrayWithArray:object];
            if(temp.count==0){

                //Save & Send Request

                [friendRequest saveInBackgroundWithBlock:^(BOOL succeeded, NSError *error) {


                    if (succeeded) {


                        UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Sent !" message:@"Friend request sent" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil, nil];
                        [alert show];



                    } else {

                        // error occurred
                    }
                }];


            }else{

                UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"FriendREquest ERROR" message:@"Friend Request is Already Submitted" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil, nil];
                [alert show];


            }


        }else{

        }

    }];
}

通过PFQuery：

您搜索＆＃34; CurrentUser＆＃34;的值＆安培; ＆＃34; SelectedUser＆＃34;在Parse.com Serve的同一行中可用！如果是，它将返回一个数组＆＃34; temp＆＃34; ...如果不是它也将返回一个数组......但如果它是0，我们将计算这个数组（所以它意味着没有其中的价值，用小词...... 没有朋友请求＆＃34;

if（NSArray * temp.count == 0）保存请求！

希望这对你有所帮助！对我来说，它的工作原理

Parse.com检查friendRequest重复iOS

1 个答案: