我编写了以下程序来从服务器获取JSON响应。代码是正确的,服务器的响应是我的期望。
#include <boost/asio/ip/tcp.hpp> //I have not shown some header for sake of readability
int main ()
{
try
{
boost::asio::ip::tcp::iostream s;
s.expires_from_now(boost::posix_time::seconds(60));
const std::string IP = "123.456.789.000";
s.connect(IP, "83");
if (!s) {
std::cout << "Unable to connect: " << s.error().message() << "\n";
}
s << "GET /MY_PATH HTTP/1.1\r\n";
s << "Host: 123.456.789.000:83\r\n";
s << "Accept: */*\r\n";
s << "Connection: close\r\n\r\n";
// Checking if response is OK.
std::string http_version;
s >> http_version;
unsigned int status_code;
s >> status_code;
std::cout<<"\nHTTP " << status_code << std::endl;
std::string status_message;
std::getline(s, status_message);
if (!s || http_version.substr(0, 5) != "HTTP/") {
std::cout << "Invalid response\n";
}
if (status_code != 200) {
std::cout << "\nResponse returned with status code " << status_code << "\n";
}
// Processing the response headers, which were terminated by a blank line.
std::string header;
while (std::getline(s, header) && header != "\r")
std::cout << header << "\n";
std::cout << "\n";
// Writing the remaining data to output.
std::cout << s.rdbuf() << "\n" << std::endl;
}// try ends here
catch (std::exception& e) {
std::cout << "Exception: " << e.what() << "\n";
}
}
来自服务器的响应如下:
HTTP 200
Cache-Control: no-cache
Pragma: no-cache
Content-Type: application/json; charset=utf-8
Expires: -1
Server: Microsoft
X-AspNet-Version: 4
X-Powered-By: ASP.NET
Date: Wed, 13 May 2015 07:49:57 GMT
Connection: close
Content-Length: 345
[{"CmdID":"30b2b2ca-376d-42bf-a931-1b92679871fc","EID":"102","CID":"00000102","NAME":"ABCD","BDAY":null,"VDATE":null,"UID":null,"ImgFileType":null,"EIMAGEBASE64STR":null},{"CmdID":"83c7d70da361-4f98-9803-1d5b7771d329","EID":"00000109","CID":"00000109","NAME":"CDEF","BDAY":null,"VDATE":null,"UID":null,"ImgFileType":null,"EIMAGEBASE64STR":null}]
现在我希望将JSON响应字符串保存到 .json 文件中。我怎么能这样做?
此时我可以存储包含HEADER和JSON字符串的完整服务器响应。但我只对JSON字符串感兴趣。
在接下来的步骤(我已经完成)中,将解析此json字符串并将其存储到sqlite3数据库中。但不幸的是,我被困在这里。
请帮助。谢谢
答案 0 :(得分:1)
嗯,实际上这是一个蛋糕散步。我很抱歉浪费你的时间。
要获取文件中的JSON字符串输出,我执行了以下操作。
// Writing the remaining data to output.
freopen("JSONoutput.json","w",stdout);
std::cout << s.rdbuf() << "\n" << std::endl;
freopen():重新使用流来打开filename指定的文件或更改其访问模式。如果指定了新文件名,则该函数首先尝试关闭任何已与stream关联的文件(第三个参数)并解除它。然后,无论该流是否成功关闭,freopen都会打开由filename指定的文件,并将其与流关联,就像fopen使用指定的模式一样。
这会创建一个文件 JSONoutput.json ,并且只有JSON字符串存储在其中,而不是其他内容。