Question

我想以毫秒（epoch）的形式将当前时间插入表中。有没有我可以使用的内置功能，这给了我时代的时间？

Answer 1

这将给你自1970年1月1日以来的毫秒：

select（sysdate - to_date（'01 -Jan-1970'，'dd-Mon-yyyy'））* 24 * 60 * 60 * 1000 from dual

Answer 2

请记住时区：

SQL> SELECT
  2     EXTRACT(DAY FROM (from_tz(CAST(SYSDATE AS TIMESTAMP), SESSIONTIMEZONE) AT TIME ZONE 'UTC' -TIMESTAMP '1970-01-01 00:00:00 +00:00'))*86400+
  3     EXTRACT(HOUR FROM (from_tz(CAST(SYSDATE AS TIMESTAMP), SESSIONTIMEZONE) AT TIME ZONE 'UTC' -TIMESTAMP '1970-01-01 00:00:00 +00:00'))*3600+
  4     EXTRACT(MINUTE FROM (from_tz(CAST(SYSDATE AS TIMESTAMP), SESSIONTIMEZONE) AT TIME ZONE 'UTC' -TIMESTAMP '1970-01-01 00:00:00 +00:00'))*60+
  5     EXTRACT(SECOND FROM (from_tz(CAST(SYSDATE AS TIMESTAMP), SESSIONTIMEZONE) AT TIME ZONE 'UTC' -TIMESTAMP '1970-01-01 00:00:00 +00:00')) date_to_epoch
  6  FROM dual;

DATE_TO_EPOCH
-------------
   1431513604

如何在PL / SQL中获得时代？

2 个答案: