Question

我正在使用pholser的端口。我必须生成匹配给定模式的字符串，如compile 'com.google.android.gms:play-services:7.3.0'。

我将Generator类扩展为：

\[a-zA-Z0-9\\.\\-\\\\;\\:\\_\\@\\[\\]\\^/\\|\\}\\{]* Length 40

它重载了一个函数：

public class InputGenerator extends Generator<TestData> {...}

现在，random具有 nextDouble（），nextInt（）等功能，但没有任何字符串！如何生成与上述模式匹配的随机字符串？

Answer 1

查找自定义生成器的以下代码段，该生成器实现generate(..)方法以返回与您发布的模式匹配的随机字符串。

public class MyCharacterGenerator extends Generator<String> {

    private static final String LOWERCASE_CHARS = "abcdefghijklmnopqrstuvwxyz";
    private static final String UPPERCASE_CHARS = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
    private static final String NUMBERS = "0123456789";
    private static final String SPECIAL_CHARS = ".-\\;:_@[]^/|}{";
    private static final String ALL_MY_CHARS = LOWERCASE_CHARS
            + UPPERCASE_CHARS + NUMBERS + SPECIAL_CHARS;
    public static final int CAPACITY = 40;

    public MyCharacterGenerator () {
        super(String.class);
    }

    @Override
    public String generate(SourceOfRandomness random, GenerationStatus status) {
        StringBuilder sb = new StringBuilder(CAPACITY);
        for (int i = 0; i < CAPACITY; i++) {
            int randomIndex = random.nextInt(ALL_MY_CHARS.length());
            sb.append(ALL_MY_CHARS.charAt(randomIndex));
        }
        return sb.toString();
    }
}

编辑一个简单的单元测试，用于演示MyCharacterGenerator类的用法。

import com.pholser.junit.quickcheck.ForAll;
import com.pholser.junit.quickcheck.From;
import static org.junit.Assert.assertTrue;
import org.junit.contrib.theories.Theories;
import org.junit.contrib.theories.Theory;
import org.junit.runner.RunWith;

@RunWith(Theories.class)
public class MyCharacterGeneratorTest {

    @Theory
    public void shouldHold(@ForAll @From(MyCharacterGenerator.class) String s) {
        // here you should add your unit test which uses the generated output
        // 
        // assertTrue(doMyUnitTest(s) == expectedResult);

        // the below lines only for demonstration and currently
        // check that the generated random has the expected
        // length and matches the expected pattern
        System.out.println("shouldHold(): " + s);
        assertTrue(s.length() == MyCharacterGenerator.CAPACITY);
        assertTrue(s.matches("[a-zA-Z0-9.\\-\\\\;:_@\\[\\]^/|}{]*"));
    }
}

由shouldHold

生成的

示例输出

shouldHold(): MD}o/LAkW/hbJVWPGdI;:RHpwo_T.lGs^DOFwu2.
shouldHold(): IT_O{8Umhkz{@PY:pmK6}Cb[Wc19GqGZjWVa@4li
shouldHold(): KQwpEz.CW28vy_/WJR3Lx2.tRC6uLIjOTQtYP/VR
shouldHold(): pc2_T4hLdZpK78UfcVmU\RTe9WaJBSGJ}5v@z[Z\
...

Answer 2

没有random.nextString()，但有一种方法可以在 junit-quickcheck-generators 库中生成随机字符串。您可以使用gen().type(String.class)创建新生成器时访问它。但是，我们似乎无法控制它。

以下是StringBuilder生成器的一个愚蠢示例，用于演示如何使用String生成器：

import com.pholser.junit.quickcheck.generator.GenerationStatus;
import com.pholser.junit.quickcheck.generator.Generator;
import com.pholser.junit.quickcheck.random.SourceOfRandomness;

public class StringBuilderGenerator extends Generator<StringBuilder> {

    public StringBuilderGenerator() {
        super(StringBuilder.class);
    }

    @Override
    public StringBuilder generate(SourceOfRandomness random, GenerationStatus status) {
        String s = gen().type(String.class).generate(random, status);
        return new StringBuilder(s);
    }
}

Junit-Quickcheck：生成匹配模式的字符串

2 个答案: