Question

我正在尝试为列表中的所有ID创建朋友关系，但我收到错误：

y already declared (line 2, column 41 (offset: 64))

"Merge (y:User{id:"21",name:"b"})
 Merge (y:User{id:"41",name:"d"})
 Merge (y:User{id:"51",name:"e"}) "
                                         ^
 Neo.ClientError.Statement.InvalidSyntax

我正在尝试创建一个具有id，name，year以及同时与现有节点关系的新用户。我该怎么做？还有其他任何方式吗？我非常感谢任何帮助。

MATCH (u:User {id:"2"})
Merge (y:User{id:"21",name:"b",year:"2010"})
Merge (y:User{id:"41",name:"d",year:"2011"})
Merge (y:User{id:"51",name:"e",,year:"2013"}) 
MERGE (u)-[:FRIEND]->(y)

Answer 1

重复使用标识符y将无效。

尝试

MATCH (u:User {id:"2"})
unwind [{id:"21",name:"b",year:"2010"},
        {id:"41",name:"d",year:"2011"},
        {id:"51",name:"e",year:"2013"}] as user
merge (y:User {id: user.id, name: user.name,year:user.year})
MERGE (u)-[:FRIEND]->(y)

如何在neo4j中创建关系并在循环中合并/创建新节点

1 个答案: