在cakephp

Question

我有2个表用户和画廊，关系就像用户hasMany Gallery.But在某些情况下查询用户模型我想获得最新的Gallery行，即ID为2而不是多行的画廊。

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Array
(
    [User] => Array
        (
            [id] => 100
            [username] => pradeepta
        )

    [Gallery] => Array
        (
            [0] => Array
                (
                    [id] => 1
                    [user_id] => 100
                    [photo] => 1111.jpg
                )
            [1] => Array
                (
                    [id] => 2
                    [user_id] => 100
                    [photo] => 222.jpg
                )
        )            
)

＆＃13;

＆＃13;

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我希望结果应该像这样

＆＃13;

＆＃13;

Array
    (
        [User] => Array
            (
                [id] => 100
                [username] => pradeepta
            )

        [Gallery] => Array
            (
                                               
                [id] => 2
                [user_id] => 100
                [photo] => 222.jpg
            )
                        
    )

＆＃13;

＆＃13;

＆＃13;

Answer 1

关系仍然需要是hasMany，但您想要更改查询的条件。如果使用连接语句，则可以限制返回的结果： -

$this->User->find(
    'first',
    array(
        'fields' => array(
            'User.*',
            'Gallery.*'
        ),
        // Join on the galleries table
        'joins' => array(
            array(
                'table' => 'galleries',
                'alias' => 'Gallery',
                'type' => 'LEFT',
                'conditions' => array(
                    'Gallery.user_id = User.id'
                )
            )
        ),
        // Order by newest galleries first
        'order' => array(
            'Gallery.id' => 'DESC'
        ),
        // Make sure we only return one instance of each user
        'group' => array(
            'User.id'
        )
    )
);

Answer 2

在您的用户模型中使用此关联

public $hasOne = array(        
        'Gallery' => array(
            'className' => 'Gallery',
            'foreignKey' => 'user_id',
            'order' => array('Gallery.id' => 'DESC')
        ),
    );