我试图播放代表生成数字的声音时出现问题。
我能够播放第一个号码但由于某种原因，以下号码没有声音出现。
目前我有一个按钮，用于测试设置声音的每个个体号码。
代码如下：已编辑
String s = tTo.getText();
String t = tFrom.getText();
try {
int x = Integer.parseInt(t);
int d = Integer.parseInt(s);
if (x >= d) {
JOptionPane
.showMessageDialog(f,
"START value is higher or Equal to END value, please enter a lower number...");
}
rand1 = (int) (Math.random() * (d + 1 - x) + x);
// rn1
if (rand1 / 10 / 10 / 10 / 10 / 10 % 10 == 0) {
rn1 = 0;
index4 = 1;
call1 = "C:/FortuneApps/Randomiser/0.wav";
} else if (rand1 / 10 / 10 / 10 / 10 / 10 % 10 == 1) {
rn1 = 1;
index4 = 6;
call1 = "C:/FortuneApps/Randomiser/1.wav";
} else if (rand1 / 10 / 10 / 10 / 10 / 10 % 10 == 2) {
rn1 = 2;
index4 = 11;
call1 = "C:/FortuneApps/Randomiser/2.wav";
} else if (rand1 / 10 / 10 / 10 / 10 / 10 % 10 == 3) {
rn1 = 3;
index4 = 16;
call1 = "C:/FortuneApps/Randomiser/3.wav";
} else if (rand1 / 10 / 10 / 10 / 10 / 10 % 10 == 4) {
rn1 = 4;
index4 = 21;
call1 = "C:/FortuneApps/Randomiser/4.wav";
} else if (rand1 / 10 / 10 / 10 / 10 / 10 % 10 == 5) {
rn1 = 5;
index4 = 26;
call1 = "C:/FortuneApps/Randomiser/5.wav";
} else if (rand1 / 10 / 10 / 10 / 10 / 10 % 10 == 6) {
rn1 = 6;
index4 = 31;
call1 = "C:/FortuneApps/Randomiser/6.wav";
} else if (rand1 / 10 / 10 / 10 / 10 / 10 % 10 == 7) {
rn1 = 7;
index4 = 36;
call1 = "C:/FortuneApps/Randomiser/7.wav";
} else if (rand1 / 10 / 10 / 10 / 10 / 10 % 10 == 8) {
rn1 = 8;
index4 = 41;
call1 = "C:/FortuneApps/Randomiser/8.wav";
} else if (rand1 / 10 / 10 / 10 / 10 / 10 % 10 == 9) {
rn1 = 9;
index4 = 46;
call1 = "C:/FortuneApps/Randomiser/9.wav";
}
等等每个随机数。
所以一切正常，因为它每次都获得第一个数字。并显示一张代表该号码的图片。
我还有一个播放声音的计时器：
代码如下：已编辑
timer8 = new Timer(20, new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
index9++;
if (index9 == 50) {
timer8.setDelay(20);
if (rand1 >= 100000) {
try {
as1 = AudioSystem.getAudioInputStream(new File(
call1));
c1 = AudioSystem.getClip();
c1.open(as1);
} catch (LineUnavailableException | IOException
| UnsupportedAudioFileException e1) {
JOptionPane
.showMessageDialog(f, "Sound has Failed");
}
c1.start();
} else if (rand1 >= 10000) {
try {
as2 = AudioSystem.getAudioInputStream(new File(
call2));
c2 = AudioSystem.getClip();
c2.open(as2);
} catch (LineUnavailableException | IOException
| UnsupportedAudioFileException e1) {
JOptionPane
.showMessageDialog(f, "Sound has Failed");
}
c2.start();
} else if (rand1 >= 1000) {
try {
as3 = AudioSystem.getAudioInputStream(new File(
call3));
c3 = AudioSystem.getClip();
c3.open(as3);
} catch (LineUnavailableException | IOException
| UnsupportedAudioFileException e1) {
JOptionPane
.showMessageDialog(f, "Sound has Failed");
}
c3.start();
} else if (rand1 >= 100) {
try {
as4 = AudioSystem.getAudioInputStream(new File(
call4));
c4 = AudioSystem.getClip();
c4.open(as4);
} catch (LineUnavailableException | IOException
| UnsupportedAudioFileException e1) {
JOptionPane
.showMessageDialog(f, "Sound has Failed");
}
c4.start();
} else if (rand1 < 100) {
try {
as5 = AudioSystem.getAudioInputStream(new File(
call5));
c5 = AudioSystem.getClip();
c5.open(as5);
} catch (LineUnavailableException | IOException
| UnsupportedAudioFileException e1) {
JOptionPane
.showMessageDialog(f, "Sound has Failed");
}
c5.start();
} else if (index9 == 100) {
if (rand1 / 10 >= 10000) {
try {
as2 = AudioSystem.getAudioInputStream(new File(
call2));
c2 = AudioSystem.getClip();
c2.open(as2);
} catch (LineUnavailableException | IOException
| UnsupportedAudioFileException e1) {
JOptionPane.showMessageDialog(f,
"Sound has Failed");
}
c2.setFramePosition(0);
c2.start();
} else if (rand1 / 10 >= 1000) {
try {
as3 = AudioSystem.getAudioInputStream(new File(
call3));
c3 = AudioSystem.getClip();
c3.open(as3);
} catch (LineUnavailableException | IOException
| UnsupportedAudioFileException e1) {
JOptionPane.showMessageDialog(f,
"Sound has Failed");
}
c3.setFramePosition(0);
c3.start();
} else if (rand1 / 10 >= 100) {
try {
as4 = AudioSystem.getAudioInputStream(new File(
call4));
c4 = AudioSystem.getClip();
c4.open(as4);
} catch (LineUnavailableException | IOException
| UnsupportedAudioFileException e1) {
JOptionPane.showMessageDialog(f,
"Sound has Failed");
}
c4.setFramePosition(0);
c4.start();
} else if (rand1 / 10 < 100) {
try {
as5 = AudioSystem.getAudioInputStream(new File(
call5));
c5 = AudioSystem.getClip();
c5.open(as5);
} catch (LineUnavailableException | IOException
| UnsupportedAudioFileException e1) {
JOptionPane.showMessageDialog(f,
"Sound has Failed");
}
}
c5.setFramePosition(0);
c5.start();
}
//and so on for each digit
timer8.stop();
}
}
}
});
timer8.setInitialDelay(5);
}
所以在代码调用的第一部分是一个字符串，它在我的电脑上找到音频文件。 我不知道它是如何只播放第一个号码而不是其他号码。 起初我以为声音可能会合在一起，所以我设置了更长的延迟，但这并没有改变任何东西。
EDITED
timer8在我的timer7结束时启动（timer7显示代表数字的最后一个图像）
这里是我试图做的事情，一旦数字被显示，剪辑将播放说祝贺号码：1,2,3
目前所有得到的是祝贺号码：1（以下号码不起作用）
我先尝过其他数字0到9，所有数字都作为第一个数字。
我已将数字的大小从6位改为2位，但仍然只播放第一个数字。
任何帮助都会很棒。