Question

我有这张桌子：

ID   CODE   WEEK  SEX
1    abc    1     F
2    abc    2     M
3    xyz    3     F
4    abc    1     M

我正在使用此查询来过滤数据：

SELECT `code`,`week`,`sex`, COUNT(`week`) as cnt 
FROM `table` 
WHERE `code` = "abc" 
and `sex` = "F" 
group by `week` 
having (`week` > 0) 
UNION ALL 
SELECT `code`,`week`,`sex`, COUNT(`week`) as cnt 
FROM `table` 
WHERE `code` = "abc" 
and `sex` = "M"
group by `week` 
having (`week` > 0)

这就是结果：

CODE   WEEK   SEX  cnt
abc    1      F    1
abc    1      M    1
abc    2      M    1

但现在我需要以这种方式显示数据：

CODE   WEEK  M  F
abc    1     1  1
abc    2     1  0

所以我有这个问题：

SELECT  
`WEEK`,`CODE`,  
GROUP_CONCAT(if(`SEX` = "F", `cnt`, NULL)) AS "F", 
GROUP_CONCAT(if(`SEX` = "M", `cnt`, NULL)) AS "M" 
FROM `temp_table`
GROUP BY `WEEK` 
ORDER BY CAST(`WEEK` AS UNSIGNED)

如何合并这2个查询？有一个更好的方法吗？

Answer 1

SELECT `WEEK`,`CODE`
, SUM(IF(`SEX` = "F", cnt, 0)) AS `F`
, SUM(IF(`SEX` = "M", cnt, 0)) AS `M`
FROM `table`
GROUP BY `WEEK`,`CODE`
;

我不确定你为什么要做那个奇怪的ORDER BY，我很确定你也想要在CODE上分组。（编辑：是的，CAST适用于周数据类型。）

如果使用第一个查询作为“来源”，请参阅以下内容：

SELECT `WEEK`,`CODE`
, SUM(IF(`SEX` = "F", 1, 0)) AS `F`
, SUM(IF(`SEX` = "M", 1, 0)) AS `M`
FROM ([original query goes in here]) `subQ`
GROUP BY `WEEK`,`CODE`
;

Rows Into Columns查询MySql

1 个答案: