第一个链接转到我问过的有关使用Heredoc语法I am unable to fix an issue concerning an HEREDOC syntax error的问题的问题
第二个链接涉及与上述链接非常相似的问题 Issue with heredoc and PHP
我遇到了一个关于从php页面中的数据库中检索数据的问题。问题与Heredoc无关,Heredoc在代码中,但问题是由于sql语法错误引起的。
<?php
// riceve l'identifictivo di un regista e ne restituisce il nome completo
function get_director($director_id) {
global $db;
$query = 'SELECT
people_fullname
FROM
people
WHERE
people_id = ' . $director_id;
$result = mysql_query($query, $db) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
extract($row);
return $people_fullname;
}
// riceve l'identificativo di un attore principale e ne restituisce il nome
// completo
function get_leadactor($leadactor_id) {
global $db;
$query = 'SELECT
people_fullname
FROM
people
WHERE
people_id = ' . $leadactor_id;
$result = mysql_query($query, $db) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
extract($row);
return $people_fullname;
}
// riceve l'identificativo di un tipo di film e ne restituisce la
//descrizione
function get_movie($type_id) {
global $db;
$query = 'SELECT
movietype_label
FROM
movietype
WHERE
movietype_id = ' . $type_id;
$result = mysql_query($query, $db) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
extract($row);
return $movietype_label;
}
// funziona per calcolare se un film ha generato un profitto, una perdita o è
// in pareggio
function calculate_differences($takings, $cost) {
$difference = $takings - $cost;
if ($difference < 0) {
$color = 'red';
$difference = '$' . abs($difference) . ' million';
} elseif ($difference > 0) {
$color ='green';
$difference = '$' . $difference . ' million';
} else {
$color = 'blue';
$difference = 'broke even';
}
return '<span style="color:' . $color . ';">' . $difference . '</span>';
}
// collegamento a MYSQL
$db = mysql_connect('localhost', 'pippo', 'pluto') or
die ('Unable to connect. Check your connection parameters. ');
mysql_select_db('moviesite', $db) or die(mysql_error($db));
// recupera le informazioni
$query = 'SELECT
movie_name, movie_year, movie_director, movie_leadactor,
movie_type, movie_running_time, movie_cost, movie_takings
FROM
movie
WHERE
movie_id = ' . $_GET['movie_id'];
$result = mysql_query($query, $db) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
$movie_name = $row['movie_name'];
$movie_director = get_director($row['movie_director']);
$movie_leadactor = get_leadactor($row['movie_leadactor']);
$movie_year = $row['movie_year'];
$movie_running_time = $row['movie_running_time'] .' mins';
$movie_takings = $row['movie_takings'] . ' million';
$movie_cost = $row['movie_cost'] . ' million';
$movie_health = $calculate_differences($row['movie_takings'],
$row['movie_cost']);
// mostra le informazioni
echo <<<ENDHTML
<html>
<head>
<title>Details and Reviews for: $movie_name</title>
</head>
<body>
<div style="text-align: center;">
<h2>$movie_name</h2>
<h3><em>Details</em></h3>
<table cellpadding="2" cellspacing="2"
style="width: 70%; margin-left: auto; margin-right: auto;">
<tr>
<td><strong>Title</strong></strong></td>
<td>$movie_name</td>
<td><strong>Release Year</strong></strong></td>
<td>$movie_year</td>
</tr><tr>
<td><strong>Movie Director</strong></td>
<td>$movie_director</td>
<td><strong>Cost</strong></td>
<td>$$movie_cost<td/>
</tr><tr>
<td><strong>Lead Actor</strong></td>
<td>$movie_leadactor</td>
<td><strong>Takings</strong></td>
<td>$$movie_takings<td/>
</tr><tr>
<td><strong>Running Time</strong></td>
<td>$movie_running_time</td>
<td><strong>Health</strong></td>
<td>$movie_health<td/>
</tr>
</table></div>
</body>
</html>
ENDHTML;
?>
这是我正在处理的语法错误:
您的SQL语法有错误;检查与MySQL服务器版本对应的手册,以便在第7行的''附近使用正确的语法
答案 0 :(得分:1)
好的,这是一个快速修复。它使代码安全或安全很少,但它将有助于此错误,至少可以防止一个注入问题。
在代码的顶部,您需要检查$_GET['movie_id']
XFINIUM.PDF。如果使用简单的isset检查来阻止url中的值不是数字,那么这也是谨慎的做法。如果传递的id不是数字(作为id应该是),那么它就像没有被传递一样好。我可能会像三元语句一样使用更简洁的东西,但这对于新的人来说更具可读性和可理解性。在构建并运行第一个查询之前(可以在声明函数之前或之后),将类似的内容放在脚本的顶部:
//if the movie id was passed in the url and is a number
if(isset($_GET['movie_id']) && is_numeric($_GET['movie_id'])){
//get it
$movie_id = $_GET['movie_id'];
} else {
//stop the code and display error.
die("Movie id not found.");
}
然后在查询中向下,将$_GET['movie_id']
替换为变量$movie_id
。
我看到的另一个问题是你有并且会遇到,$calculate_differences
是函数名,而不是变量。从之前删除$
。
此外,您应该检查第一个查询的结果是否包含is_numeric的任何行。完全有可能有人传递了不存在的电影ID。