“没有用于调用'async的匹配函数（std :: launch，<unresolved overloaded =”“function =”“type =”“>，std :: string＆amp;）'”

Question

我正在尝试使用std::async创建一个线程，但我一直收到错误 “在行

}上调用'async(std::launch, <unresolved overloaded function type>, std::string&)'”没有匹配功能

ConnectFuture = std::async(std::launch::async, Connect_T,ip);

以下是产生此行为的代码：

#include <future>

class libWrapper
{
public:

    void Connect(std::string ip);
    void Connect_T(std::string ip);

private:

    std::future<void> ConnectFuture;
};



void libWrapper::Connect(std::string ip){

    auto status = ConnectFuture.wait_for(std::chrono::seconds(0));
    if (status != std::future_status::timeout)
    {
        ConnectFuture = std::async(std::launch::async, Connect_T,ip);

    }
}

void libWrapper::Connect_T(std::string ip)
{


}

int main(int argc, char** argv) {
    libWrapper lW;
    lW.Connect("192.168.3.1");
    return 0;
}

Answer 1

它是一个成员函数，因此需要调用一个对象以及一个参数。也许它应该是静态的，或者你应该将它绑定到this：

std::async(std::launch::async, &libWrapper::Connect_T, this, ip)