Question

我的mongo记录是这样的：

{
    "_id":{"$oid":"5550b6de437f572112a29f1a"},
    "cv_count":177732,
    "gender_info": {"male_count": 50, "female_count": 32}
    "stability_info_list":[{"ratio":8.802558610369414e-05,"total_count":34081,"years":0},{"ratio":5.868372406912943e-05,"total_count":34081,"years":1}],
    "zhineng_id":"IT Manager"
}

我写这样的架构：

var ZhinengGenderSchema = new Schema({
    male_count: Number,
    female_count: Number
});

var ZhinengStabilitySchema = new Schema({
    ratio: Number,
    total_count: Number,
    years: Number
});

var ZhinengStats = new Schema({
    cv_count: Number,
    gender_info: ZhinengGenderSchema,
    stability_info_list: [ZhinengStabilitySchema],
    zhineng_id: String
})

但我得到了这个例外：

TypeError: Undefined type `undefined` at `gender_info`
Did you try nesting Schemas? You can only nest using refs or arrays.

所以mongoose不支持嵌套模式？但我的数据库已经存在，我无法更改，那么如何定义我的模式呢？

Answer 1

使用 mongoose ，您可以在Array中定义嵌套（嵌入式）模式，如下所示：

var mongoose = require('mongoose'),
    Schema = mongoose.Schema;

var bookSchema = new Schema({
    value: { type: String }
});

var authorSchema = new Schema({
    books: [bookSchema]
});

或参考

var mongoose = require('mongoose'),
    Schema = mongoose.Schema,
    ObjectId = mongoose.Schema.Types.ObjectId;

var auhtorSchema = new Schema({
  book: { type: ObjectId, ref: 'Book'}
});

您可以选择更适合您的方式

Answer 2

不要为子文档创建新的架构，你应该没问题，即：

var ZhinengGenderSchema = {
    male_count: Number,
    female_count: Number
};

var ZhinengStabilitySchema = {
    ratio: Number,
    total_count: Number
    years: Number
};

var ZhinengStats = new Schema({
    cv_count: Number,
    gender_info: ZhinengGenderSchema,
    stability_info_list: [ZhinengStabilitySchema],
    zhineng_id: String
})

Answer 3

据我所知，这是由于目前Mongoose的限制。你不能声明架构字段以包含单个子文档：您必须使用数组。请参阅：https://github.com/Automattic/mongoose/pull/585

您可以稍后设置正确的业务逻辑，以确保只添加一个子元素。

试试这个：

var ZhinengStats = new Schema({
    cv_count: Number,
    gender_info: [ZhinengGenderSchema],
    stability_info_list: [ZhinengStabilitySchema],
    zhineng_id: String
})

这样，每个子文档在MongoDB中都有自己的_id（即使它不在特定的集合中）。查看更多：http://mongoosejs.com/docs/subdocs.html

你可能也喜欢这样的东西：

var ZhinengStats = new Schema({
    cv_count: Number,
    gender_info: [{male_count: Number, female_count: Number}],
    stability_info_list: [ZhinengStabilitySchema],
    zhineng_id: String
})

在这种情况下，您将架构嵌套在另一个架构中。单个gender_info元素没有文档的尊严。

如何在mongoose中定义嵌套模式？

3 个答案: